The value of 2 cos x – cos 3x – cos 5x – 16 cos³ x sin² x is (a) 2 (b) 1 (c) 0 (d) -1
The Value of 2cosx – cos3x – cos5x – 16cos³x sin²x The Value of \(2\cos x-\cos3x-\cos5x-16\cos^3x\sin^2x\) Question Find the value of \[ 2\cos x-\cos3x-\cos5x-16\cos^3x\sin^2x \] (a) \(2\) (b) \(1\) (c) \(0\) (d) \(-1\) Solution Use the identity: \[ \cos3x+\cos5x = 2\cos4x\cos x \] Therefore, \[ 2\cos x-\cos3x-\cos5x = 2\cos x-2\cos4x\cos x \] \[ = 2\cos
The value of 2 cos x – cos 3x – cos 5x – 16 cos³ x sin² x is (a) 2 (b) 1 (c) 0 (d) -1 Read More »