Ravi Kant Kumar

If a, b, c are positive integers such that a^b^ c= 6561, then the least possible value of abc is

Minimum Value Problem šŸŽ„ Watch Video Solution Q. If \( a^{b^c} = 6561 \), find least value of \( abc \) (a) 24    (b) 36    (c) 162    (d) none of these āœļø Solution \( 6561 = 3^8 \) So \( a^{b^c} = 3^8 \) Take smallest base: \( a = 3 \Rightarrow

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If a, b, c are positive integers such that a^b^c = 256 then the maximum possible value of abc is

Maximum Value Problem šŸŽ„ Watch Video Solution Q. If \( a^{b^c} = 256 \), find maximum value of \( abc \) (a) 12    (b) 16    (c) 32    (d) 256 āœļø Solution \( 256 = 2^8 \) Possible forms: \( a^{b^c} = 2^8 \) Take \( a = 2 \Rightarrow b^c = 8

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When simplified (256)^{-(4^-3/2)} , is

Exponent Simplification šŸŽ„ Watch Video Solution Q. \( (256)^{-(4^{-3/2})} \) (a) 8    (b) \( \frac{1}{8} \)    (c) 2    (d) \( \frac{1}{2} \) āœļø Solution \( 4^{-3/2} = \frac{1}{4^{3/2}} = \frac{1}{(2^2)^{3/2}} = \frac{1}{2^3} = \frac{1}{8} \) \( (256)^{-(1/8)} = (2^8)^{-1/8} \) \( = 2^{-1} = \frac{1}{2} \) Correct Option: (d) \( \frac{1}{2} \)

When simplified (256)^{-(4^-3/2)} , is Read More Ā»