If a and b are different positive primes such that : (a + b)^-1(a^-1 + b^-1) = a^x b^y, find x + y + 2.
Find x + y + 2 Question \[ (a+b)^{-1}(a^{-1}+b^{-1}) = a^x b^y \] Solution \[ = \frac{1}{a+b} \left(\frac{1}{a} + \frac{1}{b}\right) \] \[ = \frac{1}{a+b} \cdot \frac{a+b}{ab} \] \[ = \frac{1}{ab} \] \[ = a^{-1} b^{-1} \] \[ x = -1,\quad y = -1 \] \[ x + y + 2 = -1 -1 + 2 […]