If in a ∆ ABC, tan A + tan B + tan C = 6, then cot A cot B cot C = (a) 6 (b) 1 (c) 1/6 (d) none of these
If tan A + tan B + tan C = 6, Find cot A cot B cot C If tan A + tan B + tan C = 6, Find cot A cot B cot C Question: If in a triangle \( \triangle ABC \), \[ \tan A+\tan B+\tan C=6 \] then \[ \cot A\cot