Ravi Kant Kumar

Are the following statements true or false? Give your reasons for your answer. (i) Every whole number is a natural number. (ii) Every integer is a rational number (iii) Every rational number is an integer (iv) Every natural number is a whole number. (v) Every integer is a whole number (vi) Every rational number is a whole number.

Number System True or False 📘 Question Are the following statements true or false? Give reasons: (i) Every whole number is a natural number. (ii) Every integer is a rational number. (iii) Every rational number is an integer. (iv) Every natural number is a whole number. (v) Every integer is a whole number. (vi) Every […]

Are the following statements true or false? Give your reasons for your answer. (i) Every whole number is a natural number. (ii) Every integer is a rational number (iii) Every rational number is an integer (iv) Every natural number is a whole number. (v) Every integer is a whole number (vi) Every rational number is a whole number. Read More »

The matrix A = [[0, -5, 8], [5, 0, 12], [-8, -12, 0]] is a (a) diagonal matrix (b) symmetric matrix (c) skew-symmetric matrix (d) scalar matrix

Identify Skew-Symmetric Matrix 📘 Question The matrix \[ A = \begin{bmatrix} 0 & -5 & 8 \\ 5 & 0 & 12 \\ -8 & -12 & 0 \end{bmatrix} \] is a: (a) diagonal matrix (b) symmetric matrix (c) skew-symmetric matrix (d) scalar matrix ✏️ Step-by-Step Solution Step 1: Check definition A matrix is skew-symmetric

The matrix A = [[0, -5, 8], [5, 0, 12], [-8, -12, 0]] is a (a) diagonal matrix (b) symmetric matrix (c) skew-symmetric matrix (d) scalar matrix Read More »

If A = [[2, -1, 3], [-4, 5, 1]] and B = [[2, 3], [4, -2], [1, 5]], then (a) only AB is defined (b) only BA is defined (c) AB and BA both are defined (d) AB and BA both are not defined

Check AB and BA Defined 📘 Question If \[ A = \begin{bmatrix} 2 & -1 & 3 \\ -4 & 5 & 1 \end{bmatrix} \quad (2 \times 3) \] \[ B = \begin{bmatrix} 2 & 3 \\ 4 & -2 \\ 1 & 5 \end{bmatrix} \quad (3 \times 2) \] Then: (a) only AB is

If A = [[2, -1, 3], [-4, 5, 1]] and B = [[2, 3], [4, -2], [1, 5]], then (a) only AB is defined (b) only BA is defined (c) AB and BA both are defined (d) AB and BA both are not defined Read More »

If A and B are square matrices of the same order, then (A + B)(A – B) is equal to (a) A^2 – B^2 (b) A^2 – BA – AB – B^2 (c) A^2 – B^2 + BA – AB (d) A^2 – BA + B^2 + AB

(A+B)(A-B) Matrix Identity 📘 Question If \(A\) and \(B\) are square matrices of the same order, find: \[ (A + B)(A – B) \] (a) \(A^2 – B^2\) (b) \(A^2 – BA – AB – B^2\) (c) \(A^2 – B^2 + BA – AB\) (d) \(A^2 – BA + B^2 + AB\) ✏️ Step-by-Step Solution

If A and B are square matrices of the same order, then (A + B)(A – B) is equal to (a) A^2 – B^2 (b) A^2 – BA – AB – B^2 (c) A^2 – B^2 + BA – AB (d) A^2 – BA + B^2 + AB Read More »

If A = 1/π[[sin^1(πx), tan^-1(π/x)], [sin^-1(x/π), cot^-1(πx)]], B = 1/π[[-cot^-1(πx), tan^-1(x/π)], [sin^1(x/π), -tan^-1(πx)]], then A-B is equal to

Find A – B (Inverse Trig Matrix) 📘 Question If \[ A = \frac{1}{\pi} \begin{bmatrix} \sin^{-1}(\pi x) & \tan^{-1}(1) \\ \sin^{-1}\left(\frac{x}{\pi}\right) & \cot^{-1}(\pi x) \end{bmatrix} \] \[ B = \frac{1}{\pi} \begin{bmatrix} -\cot^{-1}(\pi x) & \tan^{-1}\left(\frac{x}{\pi}\right) \\ \sin^{-1}\left(\frac{x}{\pi}\right) & -\tan^{-1}(\pi x) \end{bmatrix} \] Find \(A – B\). ✏️ Step-by-Step Solution Step 1: Subtract matrices \[ A

If A = 1/π[[sin^1(πx), tan^-1(π/x)], [sin^-1(x/π), cot^-1(πx)]], B = 1/π[[-cot^-1(πx), tan^-1(x/π)], [sin^1(x/π), -tan^-1(πx)]], then A-B is equal to Read More »

If matrix A = [aij]2×2, where aij = {1, if i ≠ j 0, if i + j, then A^2 is equal to

Find A² from aij Rule 📘 Question If \(A = [a_{ij}]_{2 \times 2}\), where: \[ a_{ij} = \begin{cases} 1, & i \ne j \\ 0, & i = j \end{cases} \] Find \(A^2\). ✏️ Step-by-Step Solution Step 1: Construct matrix For \(2 \times 2\): \[ A = \begin{bmatrix} 0 & 1 \\ 1 & 0

If matrix A = [aij]2×2, where aij = {1, if i ≠ j 0, if i + j, then A^2 is equal to Read More »

If A and B are matrices of the order, then AB^T – B^T A is a (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix

ABᵀ – BᵀA is Skew-Symmetric 📘 Question If \(A\) and \(B\) are matrices of suitable order, then: \[ AB^T – B^T A \] is a: (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix ✏️ Step-by-Step Solution Step 1: Take transpose \[ (AB^T – B^T A)^T = (AB^T)^T – (B^T A)^T \]

If A and B are matrices of the order, then AB^T – B^T A is a (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix Read More »

If A is a matrix or order m×n and B is a matrix such that AB^T and B^TA are both defined, then the order of matrix B is (a) mxn (b) n×n (c) nxm (d) mxn

Find Order of Matrix B 📘 Question If \(A\) is of order \(m \times n\) and \(B\) is such that: \[ AB^T \quad \text{and} \quad B^T A \] are both defined, find the order of matrix \(B\). (a) \(m \times n\) (b) \(n \times n\) (c) \(n \times m\) (d) \(m \times n\) ✏️ Step-by-Step

If A is a matrix or order m×n and B is a matrix such that AB^T and B^TA are both defined, then the order of matrix B is (a) mxn (b) n×n (c) nxm (d) mxn Read More »

If A and B are two matrices of order 3×m and 3×n respectively and m = n, then the order of 5A – 2B is (a) mx3 (b) 3×3 (c) mxn (d) 3xn

Find Order of 5A – 2B 📘 Question If \(A\) and \(B\) are matrices of order \(3 \times m\) and \(3 \times n\) respectively and \(m = n\), find the order of: \[ 5A – 2B \] (a) \(m \times 3\) (b) \(3 \times 3\) (c) \(m \times n\) (d) \(3 \times n\) ✏️ Step-by-Step

If A and B are two matrices of order 3×m and 3×n respectively and m = n, then the order of 5A – 2B is (a) mx3 (b) 3×3 (c) mxn (d) 3xn Read More »

If A is a square matrix such that A^2 = I, then (A – I)^3 + (A + I)^3 – 7A is equal to (a) A (b) I – A (c) I + A (d) 3A

Matrix Identity Expression 📘 Question If a square matrix \(A\) satisfies: \[ A^2 = I \] Find: \[ (A – I)^3 + (A + I)^3 – 7A \] (a) \(A\) (b) \(I – A\) (c) \(I + A\) (d) \(3A\) ✏️ Step-by-Step Solution Step 1: Use identity \[ (x-y)^3 + (x+y)^3 = 2x^3 + 6xy^2

If A is a square matrix such that A^2 = I, then (A – I)^3 + (A + I)^3 – 7A is equal to (a) A (b) I – A (c) I + A (d) 3A Read More »