Prove the following identity : (sin^3 x + cos^3 x)/(sin x + cos x) + (sin^3 x – cos^3 x)/(sin x – cos x) = 2
Prove the Identity : \[ \frac{\sin^3 x+\cos^3 x}{\sin x+\cos x} + \frac{\sin^3 x-\cos^3 x}{\sin x-\cos x} =2 \] Solution: \[ \frac{(\sin x+\cos x)(\sin^2 x-\sin x\cos x+\cos^2 x)} {\sin x+\cos x} \] \[ + \frac{(\sin x-\cos x)(\sin^2 x+\sin x\cos x+\cos^2 x)} {\sin x-\cos x} \] \[ = \sin^2 x-\sin x\cos x+\cos^2 x \] \[ + \sin^2