Find the cube of the following binomial expression : 1/x + y/3
Cube of Binomial Expression Find the Cube of the Following Binomial Expression \[ \frac{1}{x}+\frac{y}{3} \] Solution: Using identity: \[ (a+b)^3 = a^3+b^3+3ab(a+b) \] \[ \left(\frac{1}{x}+\frac{y}{3}\right)^3 \] \[ = \left(\frac{1}{x}\right)^3 + \left(\frac{y}{3}\right)^3 + 3\left(\frac{1}{x}\right)\left(\frac{y}{3}\right) \left(\frac{1}{x}+\frac{y}{3}\right) \] \[ = \frac{1}{x^3} + \frac{y^3}{27} + \frac{y}{x} \left(\frac{1}{x}+\frac{y}{3}\right) \] \[ = \frac{1}{x^3} + \frac{y^3}{27} + \frac{y}{x^2} + \frac{y^2}{3x} \] Next […]
Find the cube of the following binomial expression : 1/x + y/3 Read More »