Each set X, contains 5 elements and each set Y, contains 2 elements and 20Ur=1 Xr=S=nUr=1Yr. If each element of S belongs to exactly 10 of the Xr’^s and the exactly 4 of Yr’^s, then find the value of n.

Find the Value of n Using Sets and Counting Principle Find the Value of n Using Sets and Counting Principle Question: Each set \( X_r \) contains 5 elements and each set \( Y_r \) contains 2 elements and \[ \bigcup_{r=1}^{20}X_r=S=\bigcup_{r=1}^{n}Y_r \] If each element of \( S \) belongs to exactly 10 of the

Each set X, contains 5 elements and each set Y, contains 2 elements and 20Ur=1 Xr=S=nUr=1Yr. If each element of S belongs to exactly 10 of the Xr’^s and the exactly 4 of Yr’^s, then find the value of n. Read More »

Is it true that for any sets A and B, P(A) ⋃ P(B) = P(A⋃B) ? Justify your answer.

Is P(A) ∪ P(B) = P(A∪B)? Is P(A) ∪ P(B) = P(A∪B)? Question: Is it true that for any sets \( A \) and \( B \), \[ P(A)\cup P(B)=P(A\cup B) \] Justify your answer. Solution The statement is false. Take \[ A=\{1\}, \quad B=\{2\} \] \[ P(A)=\{\phi,\{1\}\} \] \[ P(B)=\{\phi,\{2\}\} \] \[ P(A)\cup P(B)=\{\phi,\{1\},\{2\}\}

Is it true that for any sets A and B, P(A) ⋃ P(B) = P(A⋃B) ? Justify your answer. Read More »

Using properties of sets, show that for any two sets A and B, (A⋃B) ⋂ (A⋃B’) = A

Prove That (A∪B) ∩ (A∪B’) = A Prove That (A∪B) ∩ (A∪B’) = A Question: Using properties of sets, show that for any two sets \( A \) and \( B \), \[ (A\cup B)\cap(A\cup B’)=A \] Solution Consider the left-hand side: \[ (A\cup B)\cap(A\cup B’) \] Using the distributive law, \[ =(A\cup(B\cap B’)) \]

Using properties of sets, show that for any two sets A and B, (A⋃B) ⋂ (A⋃B’) = A Read More »