If f(x) = (2^x + 2^−x)/2 , then f(x + y) f(x − y) is equals to(a) 1/2 {f(2x) + f(2y)}(b) 1/2 {f(2x) − f(2y)}(c) 1/4 {f(2x) + f(2y)}(d) 1/4 {f(2x) − f(2y)}
Find f(x+y)f(x−y) Find \( f(x+y)f(x-y) \) Question: If \[ f(x)=\frac{2^x+2^{-x}}{2} \] then \[ f(x+y)f(x-y) \] is equal to (a) \(\frac12\{f(2x)+f(2y)\}\) (b) \(\frac12\{f(2x)-f(2y)\}\) (c) \(\frac14\{f(2x)+f(2y)\}\) (d) \(\frac14\{f(2x)-f(2y)\}\) Solution: \[ f(x+y)=\frac{2^{x+y}+2^{-(x+y)}}{2} \] \[ f(x-y)=\frac{2^{x-y}+2^{-(x-y)}}{2} \] Multiplying, \[ f(x+y)f(x-y) \] \[ = \frac14 \left(2^{2x}+2^{-2x}+2^{2y}+2^{-2y}\right) \] \[ = \frac12 \left[ \frac{2^{2x}+2^{-2x}}{2} + \frac{2^{2y}+2^{-2y}}{2} \right] \] \[ = \frac12\{f(2x)+f(2y)\} \] […]