Educational

The value of m for which [{(1/7^2}^-1/3}]^1/4 = 7^m, is

Find m in Exponent Equation 🎥 Watch Video Solution Q. \( \left[\{(1/7^2)^{-2}\}^{-\frac{1}{3}}\right]^{\frac{1}{4}} = 7^m \) (a) \( -\frac{1}{3} \)    (b) \( \frac{1}{4} \)    (c) -3    (d) 2 ✏️ Solution \( \frac{1}{7^2} = 7^{-2} \) \( (7^{-2})^{-2} = 7^{4} \) \( (7^{4})^{-1/3} = 7^{-4/3} \) \( (7^{-4/3})^{1/4} = 7^{-4/12} \) \( = 7^{-1/3}

The value of m for which [{(1/7^2}^-1/3}]^1/4 = 7^m, is Read More »

If x = 2 and y = 4, then (x/y)^x-y + (y/x)^y-x =

Exponent Evaluation 🎥 Watch Video Solution Q. If \( x = 2, y = 4 \), find \( \left(\frac{x}{y}\right)^{x-y} + \left(\frac{y}{x}\right)^{y-x} \) (a) 4    (b) 8    (c) 12    (d) 2 ✏️ Solution \( \left(\frac{2}{4}\right)^{2-4} + \left(\frac{4}{2}\right)^{4-2} \) \( = \left(\frac{1}{2}\right)^{-2} + (2)^2 \) \( = 2^2 + 4 \) \( = 4

If x = 2 and y = 4, then (x/y)^x-y + (y/x)^y-x = Read More »

If a, m, n are positive integers, than {m√n√a}^mn is equal to

Nested Root Simplification 🎥 Watch Video Solution Q. \( \left(\sqrt[m]{\sqrt[n]{a}}\right)^{mn} \) (a) \( a^{mn} \)    (b) \( a \)    (c) \( a^{m/n} \)    (d) 1 ✏️ Solution \( \sqrt[n]{a} = a^{1/n} \) \( \sqrt[m]{\sqrt[n]{a}} = (a^{1/n})^{1/m} \) \( = a^{1/(mn)} \) \( \left(a^{1/(mn)}\right)^{mn} \) \( = a \) Correct Option: (b) \(

If a, m, n are positive integers, than {m√n√a}^mn is equal to Read More »

If a, b, c are positive real number ,then 5√3125a^10 b^5 c^10 is equal to

5th Root Simplification 🎥 Watch Video Solution Q. \( \sqrt[5]{3125a^{10}b^5c^{10}} \) (a) \( 5a^2bc^2 \)    (b) \( 25ab^2c \)    (c) \( 5a^3bc^3 \)    (d) \( 125a^2bc^2 \) ✏️ Solution \( 3125 = 5^5 \) \( = \sqrt[5]{5^5 \cdot a^{10} \cdot b^5 \cdot c^{10}} \) \( = 5 \cdot a^{10/5} \cdot b^{5/5} \cdot

If a, b, c are positive real number ,then 5√3125a^10 b^5 c^10 is equal to Read More »