If a and b are different positive primes such that : (a^-1b^2/a^2b^-4)^7/(a^3b^-5/a^-2b^3) = a^xb^y, find x and y
Find x and y Question \[ \frac{(a^{-1}b^2 / a^2 b^{-4})^7}{(a^3 b^{-5} / a^{-2} b^3)} = a^x b^y \] Solution \[ = \frac{(a^{-1-2} \cdot b^{2-(-4)})^7}{a^{3-(-2)} \cdot b^{-5-3}} \] \[ = \frac{(a^{-3} \cdot b^{6})^7}{a^{5} \cdot b^{-8}} \] \[ = \frac{a^{-21} \cdot b^{42}}{a^{5} \cdot b^{-8}} \] \[ = a^{-21-5} \cdot b^{42-(-8)} \] \[ = a^{-26} \cdot b^{50} \] […]