Prove that : (√(3×5^-3)/(cube root √3^(-1)√5))× 6th root √(3×5^6) = 3/5
Proof Prove: \[ \left(\frac{\sqrt{3\cdot 5^{-3}}}{\sqrt[3]{3^{-1}\cdot 5}}\right)\times \sqrt[6]{3\cdot 5^6} = \frac{3}{5} \] Proof \[ = \frac{(3\cdot 5^{-3})^{1/2}}{(3^{-1}\cdot 5)^{1/3}} \times (3\cdot 5^6)^{1/6} \] \[ = \frac{3^{1/2} \cdot 5^{-3/2}}{3^{-1/3}\cdot 5^{1/3}} \times 3^{1/6}\cdot 5 \] \[ = 3^{1/2 + 1/3 + 1/6} \cdot 5^{-3/2 – 1/3 + 1} \] \[ = 3^{\frac{3+2+1}{6}} \cdot 5^{\frac{-9-2+6}{6}} \] \[ = 3^1 \cdot […]
Prove that : (√(3×5^-3)/(cube root √3^(-1)√5))× 6th root √(3×5^6) = 3/5 Read More »