Educational

Prove that: (sin A sin 2A + sin 3A sin 6A)/(sin A cos 2A + sin 3A cos 6A) = tan 5A

Prove that (sin A sin 2A + sin 3A sin 6A)/(sin A cos 2A + sin 3A cos 6A) = tan 5A Prove that: \[ \frac{ \sin A\sin2A+\sin3A\sin6A }{ \sin A\cos2A+\sin3A\cos6A } = \tan5A \] Solution L.H.S. \[ = \frac{ \sin A\sin2A+\sin3A\sin6A }{ \sin A\cos2A+\sin3A\cos6A } \] Use identity: \[ \sin C\sin D = \frac12[\cos(C-D)-\cos(C+D)]

Prove that: (sin A sin 2A + sin 3A sin 6A)/(sin A cos 2A + sin 3A cos 6A) = tan 5A Read More »

Prove that: (sin 3A cos 4A – sin A cos 2A)/(sin 4A sin A+ cos 6A cos A) = tan 2A

Prove that (sin 3A cos 4A – sin A cos 2A)/(sin 4A sin A + cos 6A cos A) = tan 2A Prove that: \[ \frac{ \sin3A\cos4A-\sin A\cos2A }{ \sin4A\sin A+\cos6A\cos A } = \tan2A \] Solution L.H.S. \[ = \frac{ \sin3A\cos4A-\sin A\cos2A }{ \sin4A\sin A+\cos6A\cos A } \] Use identities: \[ \sin C\cos D

Prove that: (sin 3A cos 4A – sin A cos 2A)/(sin 4A sin A+ cos 6A cos A) = tan 2A Read More »

Prove that: (sin 11A sin A+ sin 7 A sin 3A)/(cos 11A sin A+ cos 7 A sin 3A) = tan 8A

Prove that (sin 11A sin A + sin 7A sin 3A)/(cos 11A sin A + cos 7A sin 3A) = tan 8A Prove that: \[ \frac{ \sin11A\sin A+\sin7A\sin3A }{ \cos11A\sin A+\cos7A\sin3A } = \tan8A \] Solution L.H.S. \[ = \frac{ \sin11A\sin A+\sin7A\sin3A }{ \cos11A\sin A+\cos7A\sin3A } \] Use identities: \[ \sin C\sin D = \frac12[\cos(C-D)-\cos(C+D)]

Prove that: (sin 11A sin A+ sin 7 A sin 3A)/(cos 11A sin A+ cos 7 A sin 3A) = tan 8A Read More »