Educational

If A and B are square matrices of the same order, explain, why in general (A + B)(A – B) ≠ A^2 – B^2

Why (A+B)(A-B) ≠ A² − B² Question If \(A\) and \(B\) are square matrices of the same order, explain why in general \[ (A + B)(A – B) \ne A^2 – B^2. \] Solution Step 1: Expand \[ (A + B)(A – B) \] \[ = A(A – B) + B(A – B) \] \[ […]

If A and B are square matrices of the same order, explain, why in general (A + B)(A – B) ≠ A^2 – B^2 Read More »

If A and B are square matrices of the same order, explain, why in general (A – B)^2 ≠ A^2 – 2AB + B^2

Why (A-B)² ≠ A² − 2AB + B² Question If \(A\) and \(B\) are square matrices of the same order, explain why in general \[ (A – B)^2 \ne A^2 – 2AB + B^2. \] Solution Step 1: Expand \((A-B)^2\) \[ (A – B)^2 = (A – B)(A – B) \] \[ = A^2 –

If A and B are square matrices of the same order, explain, why in general (A – B)^2 ≠ A^2 – 2AB + B^2 Read More »

If A and B are square matrices of the same order, explain, why in general (A + B)^2 ≠ A^2 + 2AB + B^2

Why (A+B)² ≠ A² + 2AB + B² Question If \(A\) and \(B\) are square matrices of the same order, explain why in general \[ (A + B)^2 \ne A^2 + 2AB + B^2. \] Solution Step 1: Expand \((A+B)^2\) \[ (A + B)^2 = (A + B)(A + B) \] \[ = A^2 +

If A and B are square matrices of the same order, explain, why in general (A + B)^2 ≠ A^2 + 2AB + B^2 Read More »

Let A and B be square matrix of the same order. Does (A + B)^2 = A^2 + 2AB + B^2 hold ? If not, why?

Matrix Identity (A+B)² Question Let \(A\) and \(B\) be square matrices of the same order. Does \[ (A + B)^2 = A^2 + 2AB + B^2 \] hold? If not, why? Solution Step 1: Expand \((A+B)^2\) \[ (A + B)^2 = (A + B)(A + B) \] \[ = A^2 + AB + BA +

Let A and B be square matrix of the same order. Does (A + B)^2 = A^2 + 2AB + B^2 hold ? If not, why? Read More »

A matrix X has a+b rows and a+2 column while the matrix Y has b+1 rows and a+3 columns. Both matrices XY and YX exist. Find a and b. Can you say XY and YX are of the same type? Are they equal.

Matrix Dimension Problem Question Matrix \(X\) has \((a+b)\) rows and \((a+2)\) columns. Matrix \(Y\) has \((b+1)\) rows and \((a+3)\) columns. Both \(XY\) and \(YX\) exist. Find \(a\) and \(b\). Also determine whether \(XY\) and \(YX\) are of same type and equal. Solution Step 1: Condition for \(XY\) to exist \[ \text{Columns of } X =

A matrix X has a+b rows and a+2 column while the matrix Y has b+1 rows and a+3 columns. Both matrices XY and YX exist. Find a and b. Can you say XY and YX are of the same type? Are they equal. Read More »

If A is a square matrix, using mathematical induction prove that (A^T)^n=(A^n)^T for all n ∈ N.

Transpose Power Identity Question If \(A\) is a square matrix, prove using mathematical induction that \[ (A^T)^n = (A^n)^T \quad \forall n \in \mathbb{N}. \] Solution (Mathematical Induction) Step 1: Base Case (n = 1) \[ (A^T)^1 = A^T \quad \text{and} \quad (A^1)^T = A^T \] ✔ True for \(n=1\) Step 2: Assume for \(n

If A is a square matrix, using mathematical induction prove that (A^T)^n=(A^n)^T for all n ∈ N. Read More »