April 2026

If A = [[2, -1, 3], [-4, 5, 1]] and B = [[2, 3], [4, -2], [1, 5]], then (a) only AB is defined (b) only BA is defined (c) AB and BA both are defined (d) AB and BA both are not defined

Check AB and BA Defined 📘 Question If \[ A = \begin{bmatrix} 2 & -1 & 3 \\ -4 & 5 & 1 \end{bmatrix} \quad (2 \times 3) \] \[ B = \begin{bmatrix} 2 & 3 \\ 4 & -2 \\ 1 & 5 \end{bmatrix} \quad (3 \times 2) \] Then: (a) only AB is […]

If A = [[2, -1, 3], [-4, 5, 1]] and B = [[2, 3], [4, -2], [1, 5]], then (a) only AB is defined (b) only BA is defined (c) AB and BA both are defined (d) AB and BA both are not defined Read More »

If A and B are square matrices of the same order, then (A + B)(A – B) is equal to (a) A^2 – B^2 (b) A^2 – BA – AB – B^2 (c) A^2 – B^2 + BA – AB (d) A^2 – BA + B^2 + AB

(A+B)(A-B) Matrix Identity 📘 Question If \(A\) and \(B\) are square matrices of the same order, find: \[ (A + B)(A – B) \] (a) \(A^2 – B^2\) (b) \(A^2 – BA – AB – B^2\) (c) \(A^2 – B^2 + BA – AB\) (d) \(A^2 – BA + B^2 + AB\) ✏️ Step-by-Step Solution

If A and B are square matrices of the same order, then (A + B)(A – B) is equal to (a) A^2 – B^2 (b) A^2 – BA – AB – B^2 (c) A^2 – B^2 + BA – AB (d) A^2 – BA + B^2 + AB Read More »

If A = 1/π[[sin^1(πx), tan^-1(π/x)], [sin^-1(x/π), cot^-1(πx)]], B = 1/π[[-cot^-1(πx), tan^-1(x/π)], [sin^1(x/π), -tan^-1(πx)]], then A-B is equal to

Find A – B (Inverse Trig Matrix) 📘 Question If \[ A = \frac{1}{\pi} \begin{bmatrix} \sin^{-1}(\pi x) & \tan^{-1}(1) \\ \sin^{-1}\left(\frac{x}{\pi}\right) & \cot^{-1}(\pi x) \end{bmatrix} \] \[ B = \frac{1}{\pi} \begin{bmatrix} -\cot^{-1}(\pi x) & \tan^{-1}\left(\frac{x}{\pi}\right) \\ \sin^{-1}\left(\frac{x}{\pi}\right) & -\tan^{-1}(\pi x) \end{bmatrix} \] Find \(A – B\). ✏️ Step-by-Step Solution Step 1: Subtract matrices \[ A

If A = 1/π[[sin^1(πx), tan^-1(π/x)], [sin^-1(x/π), cot^-1(πx)]], B = 1/π[[-cot^-1(πx), tan^-1(x/π)], [sin^1(x/π), -tan^-1(πx)]], then A-B is equal to Read More »

If matrix A = [aij]2×2, where aij = {1, if i ≠ j 0, if i + j, then A^2 is equal to

Find A² from aij Rule 📘 Question If \(A = [a_{ij}]_{2 \times 2}\), where: \[ a_{ij} = \begin{cases} 1, & i \ne j \\ 0, & i = j \end{cases} \] Find \(A^2\). ✏️ Step-by-Step Solution Step 1: Construct matrix For \(2 \times 2\): \[ A = \begin{bmatrix} 0 & 1 \\ 1 & 0

If matrix A = [aij]2×2, where aij = {1, if i ≠ j 0, if i + j, then A^2 is equal to Read More »

If A and B are matrices of the order, then AB^T – B^T A is a (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix

ABᵀ – BᵀA is Skew-Symmetric 📘 Question If \(A\) and \(B\) are matrices of suitable order, then: \[ AB^T – B^T A \] is a: (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix ✏️ Step-by-Step Solution Step 1: Take transpose \[ (AB^T – B^T A)^T = (AB^T)^T – (B^T A)^T \]

If A and B are matrices of the order, then AB^T – B^T A is a (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix Read More »

If A is a matrix or order m×n and B is a matrix such that AB^T and B^TA are both defined, then the order of matrix B is (a) mxn (b) n×n (c) nxm (d) mxn

Find Order of Matrix B 📘 Question If \(A\) is of order \(m \times n\) and \(B\) is such that: \[ AB^T \quad \text{and} \quad B^T A \] are both defined, find the order of matrix \(B\). (a) \(m \times n\) (b) \(n \times n\) (c) \(n \times m\) (d) \(m \times n\) ✏️ Step-by-Step

If A is a matrix or order m×n and B is a matrix such that AB^T and B^TA are both defined, then the order of matrix B is (a) mxn (b) n×n (c) nxm (d) mxn Read More »

If A and B are two matrices of order 3×m and 3×n respectively and m = n, then the order of 5A – 2B is (a) mx3 (b) 3×3 (c) mxn (d) 3xn

Find Order of 5A – 2B 📘 Question If \(A\) and \(B\) are matrices of order \(3 \times m\) and \(3 \times n\) respectively and \(m = n\), find the order of: \[ 5A – 2B \] (a) \(m \times 3\) (b) \(3 \times 3\) (c) \(m \times n\) (d) \(3 \times n\) ✏️ Step-by-Step

If A and B are two matrices of order 3×m and 3×n respectively and m = n, then the order of 5A – 2B is (a) mx3 (b) 3×3 (c) mxn (d) 3xn Read More »

If A is a square matrix such that A^2 = I, then (A – I)^3 + (A + I)^3 – 7A is equal to (a) A (b) I – A (c) I + A (d) 3A

Matrix Identity Expression 📘 Question If a square matrix \(A\) satisfies: \[ A^2 = I \] Find: \[ (A – I)^3 + (A + I)^3 – 7A \] (a) \(A\) (b) \(I – A\) (c) \(I + A\) (d) \(3A\) ✏️ Step-by-Step Solution Step 1: Use identity \[ (x-y)^3 + (x+y)^3 = 2x^3 + 6xy^2

If A is a square matrix such that A^2 = I, then (A – I)^3 + (A + I)^3 – 7A is equal to (a) A (b) I – A (c) I + A (d) 3A Read More »

If [[2x + y, 4x], [5x – 7, 4x]] = [[7, 7y – 13], [y, x + 6]], then the value of x + y is

Find x + y Using Matrix Equality 📘 Question If \[ \begin{bmatrix} 2x + y & 4x \\ 5x – 7 & 4x \end{bmatrix} = \begin{bmatrix} 7 & 7y – 13 \\ y & x + 6 \end{bmatrix} \] Find \(x + y\). ✏️ Step-by-Step Solution Step 1: Compare corresponding elements \(2x + y =

If [[2x + y, 4x], [5x – 7, 4x]] = [[7, 7y – 13], [y, x + 6]], then the value of x + y is Read More »

The number of possible matrices of order 3×3 with each entry 2 or 0 is (a) 9 (b) 27 (c) 81 (d) none of these

Number of 3×3 Matrices (0 or 2) 📘 Question The number of possible matrices of order \(3 \times 3\) with each entry 0 or 2 is: (a) 9 (b) 27 (c) 81 (d) none of these ✏️ Step-by-Step Solution Step 1: Total entries \[ 3 \times 3 = 9 \text{ entries} \] Step 2: Choices

The number of possible matrices of order 3×3 with each entry 2 or 0 is (a) 9 (b) 27 (c) 81 (d) none of these Read More »