May 2026

If x = (√3-√2)/(√3+√2) and y = (√3+√2)/(√3-√2), then x^2 + xy + y^2 =

Find the Value Find the value If \[ x = \frac{\sqrt{3} – \sqrt{2}}{\sqrt{3} + \sqrt{2}}, \quad y = \frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} – \sqrt{2}}, \] then \[ x^2 + xy + y^2 = \ ? \] Solution: \[ x = \frac{(\sqrt{3} – \sqrt{2})^2}{3 – 2} = 5 – 2\sqrt{6} \] \[ y = \frac{(\sqrt{3} + \sqrt{2})^2}{3

If x = (√3-√2)/(√3+√2) and y = (√3+√2)/(√3-√2), then x^2 + xy + y^2 = Read More »

If x = (√5+√3)/(√5-√3) and y = (√5-√3)/(√5+√3), then x + y + xy =

Find the Value Find the value If \[ x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} – \sqrt{3}} \quad \text{and} \quad y = \frac{\sqrt{5} – \sqrt{3}}{\sqrt{5} + \sqrt{3}}, \] then \[ x + y + xy = \ ? \] Solution: \[ x = \frac{(\sqrt{5} + \sqrt{3})^2}{5 – 3} = \frac{5 + 3 + 2\sqrt{15}}{2} = 4 +

If x = (√5+√3)/(√5-√3) and y = (√5-√3)/(√5+√3), then x + y + xy = Read More »