Find the values of 4/(3√3-2√2) + 3/(3√3+2√2) correct to three places of decimals, it being given that √2=1.4142, √3 = 1.732, √5 = 2.2360,√6= 2.4495 and √10 = 3.162.
Find the Value Find the value correct to three decimal places \[ \frac{4}{3\sqrt{3} – 2\sqrt{2}} + \frac{3}{3\sqrt{3} + 2\sqrt{2}}, \quad \text{where } \sqrt{2} = 1.4142,\ \sqrt{3} = 1.732 \] Solution: \[ \frac{4(3\sqrt{3} + 2\sqrt{2}) + 3(3\sqrt{3} – 2\sqrt{2})}{(3\sqrt{3})^2 – (2\sqrt{2})^2} \] \[ = \frac{12\sqrt{3} + 8\sqrt{2} + 9\sqrt{3} – 6\sqrt{2}}{27 – 8} \] \[ = […]