May 2026

Satement-1 (assertion): [{(1/7^2)^-2}^-1/3]^-1/4 = 7^-1/3 Satement-2 (reason): ((a^m)^n)^s = a^mns, a greater than, o.

Assertion Reason Exponents 🎥 Watch Video Solution Q. Assertion–Reason Type Question Statement-1: \( \left[ \{(1/7^2)^{-2}\}^{-1/3} \right]^{1/4} = 7^{-1/3} \) Statement-2: \( ((a^m)^n)^s = a^{mns},\ a>0 \) ✏️ Solution \( \frac{1}{7^2} = 7^{-2} \) \( (7^{-2})^{-2} = 7^4 \) \( (7^4)^{-1/3} = 7^{-4/3} \) \( (7^{-4/3})^{1/4} = 7^{-4/12} = 7^{-1/3} \) So Statement-1 is TRUE Statement-2 […]

Satement-1 (assertion): [{(1/7^2)^-2}^-1/3]^-1/4 = 7^-1/3 Satement-2 (reason): ((a^m)^n)^s = a^mns, a greater than, o. Read More »

If 0 less than y less than x , which statement must be true? (a) √x-√y = √x-y (b) √x+√x = √2x (c) x√y = y√x (d) √xy = √x √y

Surds MCQ 🎥 Watch Video Solution Q. If \( 0 < y < x \), which statement must be true? (a) \( \sqrt{x} – \sqrt{y} = \sqrt{x-y} \) (b) \( \sqrt{x} + \sqrt{x} = \sqrt{2x} \) (c) \( x\sqrt{y} = y\sqrt{x} \) (d) \( \sqrt{xy} = \sqrt{x}\sqrt{y} \) ✏️ Solution (a) \( \sqrt{x} – \sqrt{y}

If 0 less than y less than x , which statement must be true? (a) √x-√y = √x-y (b) √x+√x = √2x (c) x√y = y√x (d) √xy = √x √y Read More »

If a, b, c are positive integers such that a^b^ c= 6561, then the least possible value of abc is

Minimum Value Problem 🎥 Watch Video Solution Q. If \( a^{b^c} = 6561 \), find least value of \( abc \) (a) 24    (b) 36    (c) 162    (d) none of these ✏️ Solution \( 6561 = 3^8 \) So \( a^{b^c} = 3^8 \) Take smallest base: \( a = 3 \Rightarrow

If a, b, c are positive integers such that a^b^ c= 6561, then the least possible value of abc is Read More »

If a, b, c are positive integers such that a^b^c = 256 then the maximum possible value of abc is

Maximum Value Problem 🎥 Watch Video Solution Q. If \( a^{b^c} = 256 \), find maximum value of \( abc \) (a) 12    (b) 16    (c) 32    (d) 256 ✏️ Solution \( 256 = 2^8 \) Possible forms: \( a^{b^c} = 2^8 \) Take \( a = 2 \Rightarrow b^c = 8

If a, b, c are positive integers such that a^b^c = 256 then the maximum possible value of abc is Read More »