May 2026

Find the Domain and Range of f(x)=(x-2)/(2-x) Find the Domain and Range of \(f(x)=\frac{x-2}{2-x}\) Question: Find the domain and range of the real valued function: $$ f(x)=\frac{x-2}{2-x} $$ Solution Domain Given: $$ f(x)=\frac{x-2}{2-x} $$ The denominator cannot be zero. Therefore, $$ 2-x\ne0 $$ $$ x\ne2 $$ Hence, the domain is: $$ \mathbb{R}-\{2\} $$ Range Simplify […]

Find the Domain and Range of f(x)=√(x-3) Find the Domain and Range of \(f(x)=\sqrt{x-3}\) Question: Find the domain and range of the real valued function: $$ f(x)=\sqrt{x-3} $$ Solution Domain For a square root function, the expression inside the root must be non-negative. Therefore, $$ x-3\ge0 $$ $$ x\ge3 $$ Hence, the domain is: $$

Find the Domain and Range of f(x)=√(x-1) Find the Domain and Range of \(f(x)=\sqrt{x-1}\) Question: Find the domain and range of the real valued function: $$ f(x)=\sqrt{x-1} $$ Solution Domain For a square root function, the expression inside the root must be non-negative. Therefore, $$ x-1\ge0 $$ $$ x\ge1 $$ Hence, the domain is: $$

Find the Domain and Range of f(x)=(ax-b)/(cx-d) Find the Domain and Range of \(f(x)=\frac{ax-b}{cx-d}\) Question: Find the domain and range of the real valued function: $$ f(x)=\frac{ax-b}{cx-d} $$ Solution Domain Given: $$ f(x)=\frac{ax-b}{cx-d} $$ The denominator cannot be zero. Therefore, $$ cx-d\ne0 $$ $$ x\ne\frac{d}{c} $$ Hence, the domain is: $$ \mathbb{R}-\left\{\frac{d}{c}\right\} $$ Range Let

Find the Domain and Range of f(x)=(ax+b)/(bx-a) Find the Domain and Range of \(f(x)=\frac{ax+b}{bx-a}\) Question: Find the domain and range of the real valued function: $$ f(x)=\frac{ax+b}{bx-a} $$ Solution Domain Given: $$ f(x)=\frac{ax+b}{bx-a} $$ The denominator cannot be zero. Therefore, $$ bx-a\ne0 $$ $$ x\ne\frac{a}{b} $$ Hence, the domain is: $$ \mathbb{R}-\left\{\frac{a}{b}\right\} $$ Range Let

Find the Domain of f(x)=√((x-2)/(3-x)) Find the Domain of \(f(x)=\sqrt{\frac{x-2}{3-x}}\) Question: Find the domain of the following real valued function of real variable: $$ f(x)=\sqrt{\frac{x-2}{3-x}} $$ Solution Given: $$ f(x)=\sqrt{\frac{x-2}{3-x}} $$ For a square root function, the expression inside the root must be non-negative. Therefore, $$ \frac{x-2}{3-x}\ge0 $$ Critical values are: $$ x=2,\quad x=3 $$

Find the Domain of f(x)=√(9-x²) Find the Domain of \(f(x)=\sqrt{9-x^2}\) Question: Find the domain of the following real valued function of real variable: $$ f(x)=\sqrt{9-x^2} $$ Solution Given: $$ f(x)=\sqrt{9-x^2} $$ For a square root function, the expression inside the root must be non-negative. Therefore, $$ 9-x^2\ge0 $$ $$ x^2\le9 $$ $$ -3\le x\le3 $$

Find the Domain of f(x)=1/√(x²-1) Find the Domain of \(f(x)=\frac1{\sqrt{x^2-1}}\) Question: Find the domain of the following real valued function of real variable: $$ f(x)=\frac1{\sqrt{x^2-1}} $$ Solution Given: $$ f(x)=\frac1{\sqrt{x^2-1}} $$ Since the square root is in the denominator: (i) The expression inside the root must be non-negative. (ii) The denominator cannot be zero. Therefore,

Find the Domain of f(x)=√(x-2) Find the Domain of \(f(x)=\sqrt{x-2}\) Question: Find the domain of the following real valued function of real variable: $$ f(x)=\sqrt{x-2} $$ Solution Given: $$ f(x)=\sqrt{x-2} $$ For a square root function, the expression inside the root must be non-negative. Therefore, $$ x-2\ge0 $$ $$ x\ge2 $$ Hence, the domain is:

Find the Domain of f(x)=(x²+2x+1)/(x²-8x+12) Find the Domain of \(f(x)=\frac{x^2+2x+1}{x^2-8x+12}\) Question: Find the domain of the following real valued function of real variable: $$ f(x)=\frac{x^2+2x+1}{x^2-8x+12} $$ Solution Given: $$ f(x)=\frac{x^2+2x+1}{x^2-8x+12} $$ The denominator cannot be zero. $$ x^2-8x+12\ne0 $$ Factorizing: $$ (x-6)(x-2)\ne0 $$ Therefore, $$ x\ne6 \quad \text{and} \quad x\ne2 $$ Hence, all real numbers