R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x − 3. Then, R⁻¹ is(a) {(8, 11), (10, 13)}(b) {(11, 8), (13, 10)}(c) {(10, 13), (8, 11), (12, 10)}(d) none of these.

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Inverse Relation R⁻¹ | Relation Defined by y = x − 3 | Class 11 Maths Inverse Relation R⁻¹ | Relation Defined by y = x − 3 Question \( R \) is a relation from \( \{11,12,13\} \) to \( \{8,10,12\} \) defined by \[ y=x-3 \] Then, \( R^{-1} \) is (a) \( […]

R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x − 3. Then, R⁻¹ is(a) {(8, 11), (10, 13)}(b) {(11, 8), (13, 10)}(c) {(10, 13), (8, 11), (12, 10)}(d) none of these. Read More »

Let R be a relation on N defined by x + 2y = 8. The domain of R is(a) {2, 4, 8}(b) {2, 4, 6, 8}(c) {2, 4, 6}(d) {1, 2, 3, 4}.

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Domain of a Relation on Natural Numbers | x + 2y = 8 | Class 11 Maths Domain of a Relation on Natural Numbers | x + 2y = 8 Question Let \( R \) be a relation on \( N \) defined by \[ x+2y=8 \] The domain of \( R \) is (a)

Let R be a relation on N defined by x + 2y = 8. The domain of R is(a) {2, 4, 8}(b) {2, 4, 6, 8}(c) {2, 4, 6}(d) {1, 2, 3, 4}. Read More »

A relation ϕ from C to R is defined by x ϕ y ⇔ |x| = y. Which one is correct?(a) (2 + 3i) ϕ 13(b) 3 ϕ (−3)(c) (1 + i) ϕ 2(d) i ϕ 1.

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Relation from Complex Numbers to Real Numbers | Modulus Relation | Class 11 Maths Relation from Complex Numbers to Real Numbers | Modulus Relation Question A relation \( \phi \) from \( C \) to \( R \) is defined by \[ x\phi y \iff |x|=y \] Which one is correct? (a) \( (2+3i)\phi13 \)

A relation ϕ from C to R is defined by x ϕ y ⇔ |x| = y. Which one is correct?(a) (2 + 3i) ϕ 13(b) 3 ϕ (−3)(c) (1 + i) ϕ 2(d) i ϕ 1. Read More »

A relation R is defined from {2, 3, 4, 5} to {3, 6, 7, 10} by : x R y ⇔ x is relatively prime to y. Then, domain of R is(a) {2, 3, 5}(b) {3, 5}(c) {2, 3, 4}(d) {2, 3, 4, 5}.

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Domain of a Relation | Relatively Prime Relation | Class 11 Maths Domain of a Relation | Relatively Prime Relation Question A relation \( R \) is defined from \( \{2,3,4,5\} \) to \( \{3,6,7,10\} \) by \[ xRy \iff x \text{ is relatively prime to } y \] Then, domain of \( R \)

A relation R is defined from {2, 3, 4, 5} to {3, 6, 7, 10} by : x R y ⇔ x is relatively prime to y. Then, domain of R is(a) {2, 3, 5}(b) {3, 5}(c) {2, 3, 4}(d) {2, 3, 4, 5}. Read More »

If R = {(x, y) : x, y ∈ Z, x² + y² ≤ 4} is a relation on Z, then domain of R is(a) {0, 1, 2}(b) {0, −1, −2}(c) {−2, −1, 0, 1, 2}(d) none of these.

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“`html id=”relationdomain1″ Domain of a Relation on Integers | x² + y² ≤ 4 | Class 11 Maths Domain of a Relation on Integers | x² + y² ≤ 4 Question If \[ R=\{(x,y):x,y\in Z,\ x^2+y^2\le4\} \] is a relation on \( Z \), then domain of \( R \) is (a) \( \{0,1,2\} \)

If R = {(x, y) : x, y ∈ Z, x² + y² ≤ 4} is a relation on Z, then domain of R is(a) {0, 1, 2}(b) {0, −1, −2}(c) {−2, −1, 0, 1, 2}(d) none of these. Read More »

If A = {1, 2, 3}, B = {1, 4, 6, 9} and R is a relation from A to B defined by ‘x is greater than y’. The range of R is(a) {1, 4, 6, 9}(b) {4, 6, 9}(c) {1}(d) none of these.

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“`html id=”relationrange1″ Range of a Relation | Relation from A to B | Class 11 Maths Range of a Relation | Relation from A to B Question If \( A=\{1,2,3\} \), \( B=\{1,4,6,9\} \) and \( R \) is a relation from \( A \) to \( B \) defined by “\( x \) is

If A = {1, 2, 3}, B = {1, 4, 6, 9} and R is a relation from A to B defined by ‘x is greater than y’. The range of R is(a) {1, 4, 6, 9}(b) {4, 6, 9}(c) {1}(d) none of these. Read More »

Let A = {1, 2, 3}, B = {1, 3, 5}. If relation R from A to B is given by R = {(1, 3), (2, 5), (3, 3)}. Then, R⁻¹ is(a) {(3, 1), (3, 1), (5, 2)}(b) {(1, 3), (2, 5), (3, 3)}(c) {(1, 3), (5, 2)}(d) none of these.

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“`html id=”relationinverse1″ Inverse Relation R⁻¹ | Find the Inverse of a Relation | Class 11 Maths Inverse Relation R⁻¹ | Find the Inverse of a Relation Question Let \( A=\{1,2,3\} \), \( B=\{1,3,5\} \). If relation \[ R=\{(1,3),(2,5),(3,3)\} \] from \( A \) to \( B \), then \( R^{-1} \) is (a) \( \{(3,1),(3,1),(5,2)\}

Let A = {1, 2, 3}, B = {1, 3, 5}. If relation R from A to B is given by R = {(1, 3), (2, 5), (3, 3)}. Then, R⁻¹ is(a) {(3, 1), (3, 1), (5, 2)}(b) {(1, 3), (2, 5), (3, 3)}(c) {(1, 3), (5, 2)}(d) none of these. Read More »

If R is a relation on the set A = {1, 2, 3, 4, 5, 6, 7, 8, 9} given by x R y ⇔ y = 3x, then R =(a) {(3, 1), (6, 2), (8, 2), (9, 3)}(b) {(3, 1), (6, 2), (9, 3)}(c) {(3, 1), (2, 6), (3, 9)}(d) none of these.

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“`html id=”relationmaths2″ Relation on a Set | Find R if xRy ⇔ y = 3x | Class 11 Maths Relation on a Set | Find R if xRy ⇔ y = 3x Question If \( R \) is a relation on the set \( A = \{1,2,3,4,5,6,7,8,9\} \) given by \( xRy \iff y=3x \),

If R is a relation on the set A = {1, 2, 3, 4, 5, 6, 7, 8, 9} given by x R y ⇔ y = 3x, then R =(a) {(3, 1), (6, 2), (8, 2), (9, 3)}(b) {(3, 1), (6, 2), (9, 3)}(c) {(3, 1), (2, 6), (3, 9)}(d) none of these. Read More »

If A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5}, then (A − B) × (B − C) is(a) {(1, 2), (1, 5), (2, 5)}(b) {(1, 4)}(c) (1, 4)(d) none of these.

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“`html id=”mathsjax1″ Cartesian Product of Sets | Find (A – B) × (B – C) | Class 11 Maths Cartesian Product of Sets | Find (A – B) × (B – C) Question If \( A = \{1, 2, 4\} \), \( B = \{2, 4, 5\} \), \( C = \{2, 5\} \), then

If A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5}, then (A − B) × (B − C) is(a) {(1, 2), (1, 5), (2, 5)}(b) {(1, 4)}(c) (1, 4)(d) none of these. Read More »

let R be a relation on N×N defined by (a, b)R(c, d)⟺a + b = b + c for all (a, b),(c, d)∈ N×N Show that : (i) (a, b)R(a, b) for all (a, b) ∈N×N (ii) (a, b)R(c, d)⇒(c, d)R(a, b) for all (a, b),(c, d)∈ N×N (iii) (a, b)R(c, d) and (c, d)R(e, f) ⇒(a, b)R(e, f) for all (a, b),(c, d),(e, f)∈ N×N

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Show That the Relation R on N×N is Reflexive, Symmetric and Transitive Show That the Relation \(R\) on \(N\times N\) is Reflexive, Symmetric and Transitive Question Let \(R\) be a relation on \(N\times N\) defined by \[ (a,b)R(c,d)\iff a+d=b+c \] for all \[ (a,b),(c,d)\in N\times N \] Show that: (i) \[ (a,b)R(a,b) \] for all

let R be a relation on N×N defined by (a, b)R(c, d)⟺a + b = b + c for all (a, b),(c, d)∈ N×N Show that : (i) (a, b)R(a, b) for all (a, b) ∈N×N (ii) (a, b)R(c, d)⇒(c, d)R(a, b) for all (a, b),(c, d)∈ N×N (iii) (a, b)R(c, d) and (c, d)R(e, f) ⇒(a, b)R(e, f) for all (a, b),(c, d),(e, f)∈ N×N Read More »