If X = {8ⁿ − 7n − 1 : n ∈ N} and Y = {49n − 49 : n ∈ N}. Then,(a) X ⊂ Y(b) Y ⊂ X(c) X = Y(d) X ∩ Y = ϕ

If \[ X=\{8^n-7n-1:n\in N\} \] and \[ Y=\{49n-49:n\in N\} \] Then, (a) \(X\subset Y\) (b) \(Y\subset X\) (c) \(X=Y\) (d) \(X\cap Y=\phi\) Solution Consider \[ 8^n=(1+7)^n \] Using binomial expansion, \[ 8^n=1+7n+\text{terms containing }7^2 \] Therefore, \[ 8^n-7n-1 \] is divisible by \[ 49 \] Hence every element of \(X\) is a multiple of \(49\). […]

If X = {8ⁿ − 7n − 1 : n ∈ N} and Y = {49n − 49 : n ∈ N}. Then,(a) X ⊂ Y(b) Y ⊂ X(c) X = Y(d) X ∩ Y = ϕ Read More »

Let F₁ be the set of all parallelograms, F₂ the set of all rectangles, F₃ the set of all rhombuses, F₄ the set of all squares and F₅ the set of all trapeziums in a plane. Then F₁ may be equal to(a) F₂ ∩ F₃(b) F₃ ∩ F₄(c) F₂ ∪ F₃(d) F₂ ∪ F₃ ∪ F₄ ∪ F₁

Let \(F_1\) be the set of all parallelograms, \(F_2\) the set of all rectangles, \(F_3\) the set of all rhombuses, \(F_4\) the set of all squares and \(F_5\) the set of all trapeziums in a plane. Then \(F_1\) may be equal to (a) \(F_2\cap F_3\) (b) \(F_3\cap F_4\) (c) \(F_2\cup F_3\) (d) \(F_2\cup F_3\cup F_4\cup

Let F₁ be the set of all parallelograms, F₂ the set of all rectangles, F₃ the set of all rhombuses, F₄ the set of all squares and F₅ the set of all trapeziums in a plane. Then F₁ may be equal to(a) F₂ ∩ F₃(b) F₃ ∩ F₄(c) F₂ ∪ F₃(d) F₂ ∪ F₃ ∪ F₄ ∪ F₁ Read More »

The set (A ∪ B′) ∪ (B ∩ C) is equal to(a) A′ ∪ B ∪ C(b) A′ ∪ B(c) A′ ∪ C′(d) A′ ∩ B

The set \((A \cup B’) \cup (B \cap C)\) is equal to (a) \(A’ \cup B \cup C\) (b) \(A’ \cup B\) (c) \(A’ \cup C’\) (d) \(A’ \cap B\) Solution \[ (A\cup B’)\cup(B\cap C) \] \[ =A\cup[B’\cup(B\cap C)] \] Using distributive law, \[ =B’\cup(B\cap C) \] \[ =(B’\cup B)\cap(B’\cup C) \] \[ =U\cap(B’\cup C)

The set (A ∪ B′) ∪ (B ∩ C) is equal to(a) A′ ∪ B ∪ C(b) A′ ∪ B(c) A′ ∪ C′(d) A′ ∩ B Read More »

For any two sets A and B, A ∩ (A ∪ B)′ is equal to(a) A(b) B(c) ϕ(d) A ∩ B

For any two sets A and B, \(A \cap (A \cup B)’\) is equal to (a) \(A\) (b) \(B\) (c) \(\phi\) (d) \(A\cap B\) Solution \[ A\cap(A\cup B)’ \] Using De Morgan’s law, \[ =A\cap(A’\cap B’) \] \[ =(A\cap A’)\cap B’ \] \[ =\phi\cap B’ \] \[ =\phi \] Answer \[ \boxed{\phi} \] Correct option:

For any two sets A and B, A ∩ (A ∪ B)′ is equal to(a) A(b) B(c) ϕ(d) A ∩ B Read More »

Two finite sets have m and n elements. The number of subsets of the first set is 112 more than that of the second. The values of m and n are respectively(a) 4, 7(b) 7, 4(c) 4, 4(d) 7, 7

Two finite sets have \(m\) and \(n\) elements. The number of subsets of the first set is 112 more than that of the second. The values of \(m\) and \(n\) are respectively (a) \(4,7\) (b) \(7,4\) (c) \(4,4\) (d) \(7,7\) Solution Number of subsets of a set having \(m\) elements: \[ 2^m \] Number of

Two finite sets have m and n elements. The number of subsets of the first set is 112 more than that of the second. The values of m and n are respectively(a) 4, 7(b) 7, 4(c) 4, 4(d) 7, 7 Read More »

Suppose A₁, A₂,….,A₃₀ are thirty sets each having 5 elements and B₁, B₂,….,Bₙ are n sets each with 3 elements, let⋃₁³⁰ Aᵢ = ⋃₁ⁿ Bⱼ = S and each element of S belongs to exactly 10 of the Aᵢ’s and exactly 9 of the Bⱼ’s, then n is equal to(a) 15(b) 3(c) 45(d) 35

Suppose \(A_1, A_2,\ldots,A_{30}\) are thirty sets each having 5 elements and \(B_1, B_2,\ldots,B_n\) are \(n\) sets each with 3 elements. Let \[ \bigcup_{i=1}^{30} A_i=\bigcup_{j=1}^{n} B_j=S \] and each element of \(S\) belongs to exactly 10 of the \(A_i\)’s and exactly 9 of the \(B_j\)’s, then \(n\) is equal to (a) 15 (b) 3 (c) 45

Suppose A₁, A₂,….,A₃₀ are thirty sets each having 5 elements and B₁, B₂,….,Bₙ are n sets each with 3 elements, let⋃₁³⁰ Aᵢ = ⋃₁ⁿ Bⱼ = S and each element of S belongs to exactly 10 of the Aᵢ’s and exactly 9 of the Bⱼ’s, then n is equal to(a) 15(b) 3(c) 45(d) 35 Read More »

In a class of 175 students the following data shows the number of students opting one or more subjects. Mathematics 100; Physics 70; Chemistry 40; Mathematics and Physics 30; Mathematics and Chemistry 28; Physics and Chemistry 23; Mathematics, Physics and Chemistry 18. How many students have offered Mathematics alone?(a) 35(b) 48(c) 60(d) 22

In a class of 175 students the following data shows the number of students opting one or more subjects. Mathematics \(=100\) Physics \(=70\) Chemistry \(=40\) Mathematics and Physics \(=30\) Mathematics and Chemistry \(=28\) Physics and Chemistry \(=23\) Mathematics, Physics and Chemistry \(=18\) How many students have offered Mathematics alone? (a) 35 (b) 48 (c) 60

In a class of 175 students the following data shows the number of students opting one or more subjects. Mathematics 100; Physics 70; Chemistry 40; Mathematics and Physics 30; Mathematics and Chemistry 28; Physics and Chemistry 23; Mathematics, Physics and Chemistry 18. How many students have offered Mathematics alone?(a) 35(b) 48(c) 60(d) 22 Read More »

Two finite sets have m and n elements. The number of elements in the power set of first set is 48 more than the total number of elements in power set of the second set. Then, the values of m and n are:(a) 7, 6(b) 6, 3(c) 6, 4(d) 7, 4

Two finite sets have \(m\) and \(n\) elements. The number of elements in the power set of first set is 48 more than the total number of elements in power set of the second set. Then, the values of \(m\) and \(n\) are: (a) \(7,6\) (b) \(6,3\) (c) \(6,4\) (d) \(7,4\) Solution Number of elements

Two finite sets have m and n elements. The number of elements in the power set of first set is 48 more than the total number of elements in power set of the second set. Then, the values of m and n are:(a) 7, 6(b) 6, 3(c) 6, 4(d) 7, 4 Read More »

An investigator interviewed 100 students to determine the performance of three drinks: milk, coffee and tea. The investigator reported that 10 students take all three drinks milk, coffee and tea; 20 students take milk and coffee; 25 students take milk and tea; 20 students take coffee and tea; 12 students take milk only; 5 students take coffee only and 8 students take tea only. Then the number of students who did not take any of the three drinks is(a) 10(b) 20(c) 25(d) 30

An investigator interviewed 100 students to determine the performance of three drinks: milk, coffee and tea. The investigator reported that \[ n(M\cap C\cap T)=10 \] \[ n(M\cap C)=20 \] \[ n(M\cap T)=25 \] \[ n(C\cap T)=20 \] Milk only \(=12\), Coffee only \(=5\), Tea only \(=8\) Solution Students taking only two drinks: \[ (M\cap C)\text{

An investigator interviewed 100 students to determine the performance of three drinks: milk, coffee and tea. The investigator reported that 10 students take all three drinks milk, coffee and tea; 20 students take milk and coffee; 25 students take milk and tea; 20 students take coffee and tea; 12 students take milk only; 5 students take coffee only and 8 students take tea only. Then the number of students who did not take any of the three drinks is(a) 10(b) 20(c) 25(d) 30 Read More »