If X = {8ⁿ − 7n − 1 : n ∈ N} and Y = {49n − 49 : n ∈ N}. Then,(a) X ⊂ Y(b) Y ⊂ X(c) X = Y(d) X ∩ Y = ϕ
If \[ X=\{8^n-7n-1:n\in N\} \] and \[ Y=\{49n-49:n\in N\} \] Then, (a) \(X\subset Y\) (b) \(Y\subset X\) (c) \(X=Y\) (d) \(X\cap Y=\phi\) Solution Consider \[ 8^n=(1+7)^n \] Using binomial expansion, \[ 8^n=1+7n+\text{terms containing }7^2 \] Therefore, \[ 8^n-7n-1 \] is divisible by \[ 49 \] Hence every element of \(X\) is a multiple of \(49\). […]