If 3x = a + b + c, Find the Value of (x − a)³ + (x − b)³ + (x − c)³ − 3(x − a)(x − b)(x − c) If 3x = a + b + c, Find the Value of (x − a)³ + (x − b)³ + (x − c)³ − […]

Factorization of x⁴ + 4 Factorization of x⁴ + 4 The expression \[ x^4+4 \] can be factorized as (a) \((x^2+2x+2)(x^2-2x+2)\) (b) \((x^2+2x+2)(x^2+2x-2)\) (c) \((x^2-2x-2)(x^2-2x+2)\) (d) \((x^2+2)(x^2-2)\) Solution \[ x^4+4 \] \[ =x^4+4x^2+4-4x^2 \] \[ =(x^2+2)^2-(2x)^2 \] \[ =(x^2+2x+2)(x^2-2x+2) \] Therefore, \[ \boxed{(a)\ (x^2+2x+2)(x^2-2x+2)} \] Next Question / Full Exercise

Factors of x³ − 7x + 6 Factors of x³ − 7x + 6 The factors of \[ x^3-7x+6 \] are (a) \(x(x-6)(x-1)\) (b) \((x^2-6)(x-1)\) (c) \((x+1)(x+2)(x-3)\) (d) \((x-1)(x+3)(x-2)\) Solution \[ x^3-7x+6 \] \[ =x^3-x^2+x^2-7x+6 \] \[ =x^2(x-1)+x(x-1)-6(x-1) \] \[ =(x-1)(x^2+x-6) \] \[ =(x-1)(x+3)(x-2) \] Therefore, \[ \boxed{(d)\ (x-1)(x+3)(x-2)} \] Next Question / Full Exercise

Factors of x² + 4y² + 4y − 4xy − 2x − 8 Factors of x² + 4y² + 4y − 4xy − 2x − 8 The factors of \[ x^2+4y^2+4y-4xy-2x-8 \] are (a) \((x-2y-4)(x-2y+2)\) (b) \((x-y+2)(x-4y-4)\) (c) \((x+2y-4)(x+2y+2)\) (d) none of these Solution \[ x^2+4y^2+4y-4xy-2x-8 \] \[ =x^2-4xy+4y^2-2x+4y-8 \] \[ =(x-2y)^2-2(x-2y)-8 \] Let \[

Factors of x⁴ + x² + 25 Factors of x⁴ + x² + 25 The factors of \[ x^4+x^2+25 \] are (a) \((x^2+3x+5)(x^2-3x+5)\) (b) \((x^2+3x+5)(x^2+3x-5)\) (c) \((x^2+x+5)(x^2-x+5)\) (d) none of these Solution \[ x^4+x^2+25 \] \[ =x^4+10x^2+25-9x^2 \] \[ =(x^2+5)^2-(3x)^2 \] \[ =(x^2+5+3x)(x^2+5-3x) \] \[ =(x^2+3x+5)(x^2-3x+5) \] Therefore, \[ \boxed{(a)\ (x^2+3x+5)(x^2-3x+5)} \] Next Question /

Factors of a² − 1 − 2x − x² Factors of a² − 1 − 2x − x² The factors of \[ a^2-1-2x-x^2 \] are (a) \((a-x+1)(a-x-1)\) (b) \((a+x-1)(a-x+1)\) (c) \((a+x+1)(a-x-1)\) (d) none of these Solution \[ a^2-1-2x-x^2 \] \[ =a^2-(x^2+2x+1) \] \[ =a^2-(x+1)^2 \] \[ =(a+x+1)(a-x-1) \] Therefore, \[ \boxed{(c)\ (a+x+1)(a-x-1)} \] Next Question

Value of {(0.013)³ + (0.007)³}/{(0.013)² − 0.013×0.007 + (0.007)²} Value of {(0.013)³ + (0.007)³}/{(0.013)² − 0.013×0.007 + (0.007)²} The value of \[ \frac{(0.013)^3+(0.007)^3} {(0.013)^2-(0.013)(0.007)+(0.007)^2} \] is (a) \(0.006\) (b) \(0.02\) (c) \(0.0091\) (d) \(0.00185\) Solution \[ \frac{a^3+b^3}{a^2-ab+b^2}=a+b \] Here, \[ a=0.013,\quad b=0.007 \] Therefore, \[ =0.013+0.007 \] \[ =0.02 \] Therefore, \[ \boxed{(b)\ 0.02} \]

Value of {(2.3)³ − 0.027}/{(2.3)² + 0.69 + 0.09} Value of {(2.3)³ − 0.027}/{(2.3)² + 0.69 + 0.09} The value of \[ \frac{(2.3)^3-0.027}{(2.3)^2+0.69+0.09} \] is (a) \(2\) (b) \(3\) (c) \(2.327\) (d) \(2.273\) Solution \[ \frac{(2.3)^3-(0.3)^3}{(2.3)^2+(2.3)(0.3)+(0.3)^2} \] Using identity: \[ \frac{a^3-b^3}{a^2+ab+b^2}=a-b \] \[ =2.3-0.3 \] \[ =2 \] Therefore, \[ \boxed{(a)\ 2} \] Next Question

Factorization of (a − b)³ + (b − c)³ + (c − a)³ Factorization of (a − b)³ + (b − c)³ + (c − a)³ The expression \[ (a-b)^3+(b-c)^3+(c-a)^3 \] can be factorized as (a) \((a-b)(b-c)(c-a)\) (b) \(3(a-b)(b-c)(c-a)\) (c) \(-3(a-b)(b-c)(c-a)\) (d) \((a+b+c)(a^2+b^2+c^2-ab-bc-ca)\) Solution Let \[ x=a-b,\quad y=b-c,\quad z=c-a \] Then, \[ x+y+z=(a-b)+(b-c)+(c-a)=0 \] Using

Factorization of (x + y)³ − (x − y)³ Factorization of (x + y)³ − (x − y)³ \[ (x+y)^3-(x-y)^3 \] can be factorized as (a) \(2y(3x^2+y^2)\) (b) \(2x(3x^2+y^2)\) (c) \(2y(3y^2+x^2)\) (d) \(2x(x^2+3y^2)\) Solution \[ (x+y)^3=x^3+3x^2y+3xy^2+y^3 \] \[ (x-y)^3=x^3-3x^2y+3xy^2-y^3 \] \[ (x+y)^3-(x-y)^3 \] \[ =x^3+3x^2y+3xy^2+y^3 -x^3+3x^2y-3xy^2+y^3 \] \[ =6x^2y+2y^3 \] \[ =2y(3x^2+y^2) \] Therefore, \[