Find the value of 64x^3 – 125z^3, if 4x – 5z = 16 and xz = 12.

Find the Value Using Identity Find the Value of \(64x^3-125z^3\), if \(4x-5z=16\) and \(xz=12\) Solution: Using identity: \[ a^3-b^3=(a-b)^3+3ab(a-b) \] Here, \[ a=4x,\quad b=5z \] \[ a-b=16 \] \[ ab=(4x)(5z)=20xz=20(12)=240 \] \[ 64x^3-125z^3 = (16)^3+3(240)(16) \] \[ = 4096+11520 \] \[ =15616 \] Next Question / Full Exercise

Find the value of 64x^3 – 125z^3, if 4x – 5z = 16 and xz = 12. Read More »

Find the value of 27x^3 + 8y^3, if 3x + 2y = 20 and xy = 14/9

Find the Value Using Identity Find the Value of \(27x^3+8y^3\), if \(3x+2y=20\) and \(xy=\frac{14}{9}\) Solution: Using identity: \[ a^3+b^3=(a+b)^3-3ab(a+b) \] Here, \[ a=3x,\quad b=2y \] \[ a+b=20 \] \[ ab=(3x)(2y)=6xy =6\left(\frac{14}{9}\right) =\frac{28}{3} \] \[ 27x^3+8y^3 = (20)^3-3\left(\frac{28}{3}\right)(20) \] \[ = 8000-560 \] \[ =7440 \] Next Question / Full Exercise

Find the value of 27x^3 + 8y^3, if 3x + 2y = 20 and xy = 14/9 Read More »

If x + 1/x = 3, calculate x^2 + 1/x^2, x^3 + 1/x^3 and x^4 + 1/x^4.

Calculate Values Using Identity Calculate the Following Values \[ x+\frac{1}{x}=3 \] Find: \[ x^2+\frac{1}{x^2},\quad x^3+\frac{1}{x^3},\quad x^4+\frac{1}{x^4} \] Solution: Using identity: \[ \left(x+\frac{1}{x}\right)^2 = x^2+\frac{1}{x^2}+2 \] \[ (3)^2 = x^2+\frac{1}{x^2}+2 \] \[ 9 = x^2+\frac{1}{x^2}+2 \] \[ x^2+\frac{1}{x^2} = 7 \] Now using identity: \[ a^3+b^3=(a+b)^3-3ab(a+b) \] \[ x^3+\frac{1}{x^3} = \left(x+\frac{1}{x}\right)^3 -3\left(x\cdot\frac{1}{x}\right)\left(x+\frac{1}{x}\right) \] \[ = (3)^3-3(1)(3)

If x + 1/x = 3, calculate x^2 + 1/x^2, x^3 + 1/x^3 and x^4 + 1/x^4. Read More »