Find the value of 27x^3 + 8y^3, if 3x + 2y = 14 and xy = 8
Find the Value Using Identity Find the Value \[ 3x+2y=14 \] \[ xy=8 \] Find: \[ 27x^3+8y^3 \] Solution: Using identity: \[ a^3+b^3=(a+b)^3-3ab(a+b) \] Here, \[ a=3x,\quad b=2y \] \[ a+b=14 \] \[ ab=(3x)(2y)=6xy=6(8)=48 \] \[ 27x^3+8y^3 = (14)^3-3(48)(14) \] \[ = 2744-2016 \] \[ =728 \] Next Question / Full Exercise
Find the value of 27x^3 + 8y^3, if 3x + 2y = 14 and xy = 8 Read More »