The positive square root of 7 + √48, is
Simplify Surd Find the positive square root \[ \sqrt{7 + \sqrt{48}} \] (a) \(7 + 2\sqrt{3}\) \quad (b) \(7 + \sqrt{3}\) \quad (c) \(2 + \sqrt{3}\) \quad (d) \(3 + \sqrt{2}\) Solution: \[ \sqrt{48} = 4\sqrt{3} \] \[ \sqrt{7 + 4\sqrt{3}} = \sqrt{a} + \sqrt{b} \] \[ a + b = 7,\quad ab = 12
The positive square root of 7 + √48, is Read More »