If x = 7 + 4√3 and xy = 1, then 1/x^2 + 1/y^2 =
Find the Value Find the value \[ x = 7 + 4\sqrt{3}, \quad xy = 1 \] Solution: \[ y = \frac{1}{x} = 7 – 4\sqrt{3} \] \[ x + y = (7 + 4\sqrt{3}) + (7 – 4\sqrt{3}) = 14 \] \[ xy = 1 \] \[ x^2 + y^2 = (x + y)^2 […]
If x = 7 + 4√3 and xy = 1, then 1/x^2 + 1/y^2 = Read More »