Find (AB)^T Find (AB)T Given: \[ A = \begin{bmatrix} 2 & 4 & -1 \\ -1 & 0 & 2 \end{bmatrix}, \quad B = \begin{bmatrix} 3 & 4 \\ -1 & 2 \\ 2 & 1 \end{bmatrix} \] Step 1: Find AB \[ AB = \begin{bmatrix} 2 & 4 & -1 \\ -1 & 0 […]
If A=[[2, 4, -1], [-1, 0, 2]], B=[[3, 4], [-1, 2], [2, 1]], find (AB)^T Read More »
Verify (AB)^T = B^T A^T Verify that (AB)T = BTAT Given: \[ A = \begin{bmatrix} -2 \\ 4 \\ 5 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 3 & -6 \end{bmatrix} \] To Verify: \[ (AB)^T = B^T A^T \] Step 1: Find AB \[ AB = \begin{bmatrix} -2 \\ 4 \\ 5 \end{bmatrix} \begin{bmatrix}
If A = [[-2], [4], [5]], B = [1, 3, -6], verify that (AB)^T = B^TA^T Read More »
Verify Matrix Transpose Properties Verify Matrix Transpose Properties Given: \[ A = \begin{bmatrix} 1 & -1 & 0 \\ 2 & 1 & 3 \\ 1 & 2 & 1 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 1 & 3 \\ 0 & 1 & 1 \end{bmatrix} \] Step
Verify (AB)^T = B^T A^T Verify that (AB)T = BTAT Given: \( A = \begin{bmatrix} 3 \\ 5 \\ 2 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 0 & 4 \end{bmatrix} \) To Verify: \( (AB)^T = B^T A^T \) Step 1: Find AB \[ AB = \begin{bmatrix} 3 \\ 5 \\ 2 \end{bmatrix} \begin{bmatrix}
If A = [[3], [5], [2]] and B = [1, 0, 4], verify that (AB)^T = B^TA^T. Read More »
Verify (AB)^T = B^T A^T Verify that (AB)T = BTAT Given: \( A = \begin{bmatrix} 2 & -3 \\ -7 & 5 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 0 \\ 2 & -4 \end{bmatrix} \) To Verify: \( (AB)^T = B^T A^T \) Step 1: Find AB \[ AB = \begin{bmatrix} 2 & -3
Let A = [[2, -3],[-7, 5]] and B = [[1, 0],[2, -4]], verify that (AB)^T = B^TA^T Read More »
Verify (A – B)^T = A^T – B^T Verify that (A – B)T = AT – BT Given: \( A = \begin{bmatrix} 2 & -3 \\ -7 & 5 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 0 \\ 2 & -4 \end{bmatrix} \) To Verify: \( (A – B)^T = A^T – B^T \) Step
Let A = [[2, -3],[-7, 5]] and B=[[1, 0],[2, -4]], verify that (A – B)^T = A^T – B^T Read More »
Verify (A + B)^T = A^T + B^T Verify that (A + B)T = AT + BT Given: \( A = \begin{bmatrix} 2 & -3 \\ -7 & 5 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 0 \\ 2 & -4 \end{bmatrix} \) To Verify: \( (A + B)^T = A^T + B^T \) Step
Let A = [[2, -3], [-7, 5]] and B = [[1, 0], [2, -4]], verify that (A + B)^T = A^T + B^T Read More »
Verify (2A)^T = 2A^T | Matrix Transpose Property Verify that (2A)T = 2AT Given: \( A = \begin{bmatrix} 2 & -3 \\ -7 & 5 \end{bmatrix} \) To Verify: \( (2A)^T = 2A^T \) Step 1: Find 2A \[ 2A = 2 \begin{bmatrix} 2 & -3 \\ -7 & 5 \end{bmatrix} = \begin{bmatrix} 4 &
Let A = [[2, -3],[-7, 5]] and B=[[1, 0],[2, -4]], verify that (2A)^T = 2A^T Read More »
Bond Investment using Matrix Question A trust invested money in two bonds: 10% and 12%. Total interest = ₹2800 If investments are interchanged, interest becomes ₹2700. Find the investment using matrix method. Solution Step 1: Let \[ x = \text{amount at 10%}, \quad y = \text{amount at 12%} \] Step 2: Form Equations \[ 0.10x
Income Expenditure Matrix Problem Question The monthly incomes of Aryan and Babbar are in the ratio \(3:4\) and their expenditures are in the ratio \(5:7\). Each saves ₹15000 per month. Find their monthly incomes using matrix method. Solution Step 1: Assume \[ \text{Income} = 3x,\ 4x \] \[ \text{Expenditure} = 5y,\ 7y \] Step 2: