Educational

Let A={1,2,…,n} and B={a,b}. Then the number of subjections from A into B is (a) nP2 (b) 2^n – 2 (c) 2^n – 1 (d) nC2

Number of Surjections Find Number of Surjections πŸŽ₯ Video Explanation πŸ“ Question Let \(A=\{1,2,\dots,n\}\) and \(B=\{a,b\}\). Find number of surjections from \(A\) to \(B\). (a) \(nP_2\) (b) \(2^n – 2\) (c) \(2^n – 1\) (d) \(nC_2\) βœ… Solution πŸ”Ή Step 1: Total Functions Each element of \(A\) can map to either \(a\) or \(b\): \[ […]

Let A={1,2,…,n} and B={a,b}. Then the number of subjections from A into B is (a) nP2 (b) 2^n – 2 (c) 2^n – 1 (d) nC2 Read More Β»

Let f : Rβ†’R be given by f(x)=tan x .Then, f^-1(1) is (a) Ο€/4 (b) {nΟ€+Ο€/4 : n∈Z} (c) does not exist (d) none of these

Inverse Trigonometric Function Find \(f^{-1}(1)\) πŸŽ₯ Video Explanation πŸ“ Question Let \( f:\mathbb{R} \to \mathbb{R} \), \[ f(x)=\tan x \] Find \(f^{-1}(1)\). (a) \(\frac{\pi}{4}\) (b) \(\{n\pi+\frac{\pi}{4}: n\in\mathbb{Z}\}\) (c) does not exist (d) none of these βœ… Solution πŸ”Ή Step 1: Check Invertibility \(\tan x\) is periodic: \[ \tan x = \tan(x+n\pi) \] So it is

Let f : Rβ†’R be given by f(x)=tan x .Then, f^-1(1) is (a) Ο€/4 (b) {nΟ€+Ο€/4 : n∈Z} (c) does not exist (d) none of these Read More Β»

Let f : Rβ†’R be given by f(x) = x^2 – 3. Then ,f^-1 is given by (a) √x + 3 (b) √x + 3 (c) x + √3 (d) none of these

Inverse Function Find \(f^{-1}(x)\) πŸŽ₯ Video Explanation πŸ“ Question Let \( f:\mathbb{R} \to \mathbb{R} \), \[ f(x)=x^2-3 \] (a) \(\sqrt{x+3}\) (b) \(-\sqrt{x+3}\) (c) \(x+\sqrt{3}\) (d) none of these βœ… Solution πŸ”Ή Step 1: Check Injectivity \[ f(x)=x^2-3 \Rightarrow f(2)=1,\; f(-2)=1 \] Different inputs β†’ same output β‡’ ❌ Not one-one — πŸ”Ή Step 2: Conclusion

Let f : Rβ†’R be given by f(x) = x^2 – 3. Then ,f^-1 is given by (a) √x + 3 (b) √x + 3 (c) x + √3 (d) none of these Read More Β»

Let f(x) = x^3 be a function with domain {0, 1, 2, 3}. Then domain of f^βˆ’1 is (a) {3, 2, 1, 0} (b) {0,-1,-2, -3} (c) {0, 1, 8, 27} (d) {0,-1,-8, -27}

Domain of Inverse Function Find Domain of \(f^{-1}\) πŸŽ₯ Video Explanation πŸ“ Question Let: \[ f(x)=x^3 \] Domain of \(f\): \(\{0,1,2,3\}\) Find domain of \(f^{-1}\). (a) \(\{3,2,1,0\}\) (b) \(\{0,-1,-2,-3\}\) (c) \(\{0,1,8,27\}\) (d) \(\{0,-1,-8,-27\}\) βœ… Solution πŸ”Ή Step 1: Find Range of \(f\) \[ f(0)=0,\quad f(1)=1,\quad f(2)=8,\quad f(3)=27 \] Range: \[ \{0,1,8,27\} \] — πŸ”Ή Step

Let f(x) = x^3 be a function with domain {0, 1, 2, 3}. Then domain of f^βˆ’1 is (a) {3, 2, 1, 0} (b) {0,-1,-2, -3} (c) {0, 1, 8, 27} (d) {0,-1,-8, -27} Read More Β»

If f : Rβ†’R is given by f(x) = x^3 + 3, then f^βˆ’1(x) is equal to (a) x^1/3 -3 (b) x^1/3 +3 (c) (x – 3)^1/3 (d) (x + 3)^1/3

Inverse Function Find \(f^{-1}(x)\) πŸŽ₯ Video Explanation πŸ“ Question Let \( f:\mathbb{R} \to \mathbb{R} \), \[ f(x)=x^3+3 \] (a) \(x^{1/3}-3\) (b) \(x^{1/3}+3\) (c) \((x-3)^{1/3}\) (d) \((x+3)^{1/3}\) βœ… Solution πŸ”Ή Step 1: Let \(y=f(x)\) \[ y=x^3+3 \] — πŸ”Ή Step 2: Solve for \(x\) \[ x^3=y-3 \] \[ x=(y-3)^{1/3} \] — πŸ”Ή Step 3: Replace \(y\)

If f : Rβ†’R is given by f(x) = x^3 + 3, then f^βˆ’1(x) is equal to (a) x^1/3 -3 (b) x^1/3 +3 (c) (x – 3)^1/3 (d) (x + 3)^1/3 Read More Β»

If f(x) = sin^2 x and the composite function g(f(x)) = ∣sinx∣, then g(x) is equal to (a) √x-1 (b) √x (c) √x+1 (d) – √x

Find g(x) Find \(g(x)\) πŸŽ₯ Video Explanation πŸ“ Question Given: \[ f(x)=\sin^2 x \] \[ g(f(x))=|\sin x| \] Find \(g(x)\). (a) \(\sqrt{x-1}\) (b) \(\sqrt{x}\) (c) \(\sqrt{x+1}\) (d) \(-\sqrt{x}\) βœ… Solution πŸ”Ή Step 1: Substitute \(f(x)\) \[ g(\sin^2 x)=|\sin x| \] — πŸ”Ή Step 2: Express RHS \[ |\sin x|=\sqrt{\sin^2 x} \] — πŸ”Ή Step 3:

If f(x) = sin^2 x and the composite function g(f(x)) = ∣sinx∣, then g(x) is equal to (a) √x-1 (b) √x (c) √x+1 (d) – √x Read More Β»

If g(x) = x^2 + x βˆ’ 2 and 1/2 gof(x) = 2x^2 βˆ’ 5x + 2, then f(x) is equal to

Find f(x) Find \(f(x)\) πŸŽ₯ Video Explanation πŸ“ Question Given: \[ g(x)=x^2+x-2 \] \[ \frac{1}{2}g(f(x))=2x^2-5x+2 \] Find \(f(x)\). βœ… Solution πŸ”Ή Step 1: Remove Fraction \[ g(f(x))=4x^2-10x+4 \] — πŸ”Ή Step 2: Substitute \(g(x)\) \[ (f(x))^2 + f(x) -2 = 4x^2-10x+4 \] — πŸ”Ή Step 3: Rearrange \[ (f(x))^2 + f(x) – (4x^2-10x+6)=0 \] —

If g(x) = x^2 + x βˆ’ 2 and 1/2 gof(x) = 2x^2 βˆ’ 5x + 2, then f(x) is equal to Read More Β»

Let [x] denote the greatest integer less than or equal to x . If f(x)=sin^βˆ’1x, g(x)=[x^2] and h(x)=2x, 1/2≀x≀1/√2, then

Function Composition Evaluate \(f(g(h(x)))\) πŸŽ₯ Video Explanation πŸ“ Question Let: \[ f(x)=\sin^{-1}x,\quad g(x)=[x^2],\quad h(x)=2x \] where \([x]\) denotes greatest integer ≀ \(x\), and \[ \frac{1}{2} \le x \le \frac{1}{\sqrt{2}} \] Find \(f(g(h(x)))\). βœ… Solution πŸ”Ή Step 1: Find \(h(x)\) \[ h(x)=2x \] \[ 1 \le 2x \le \sqrt{2} \] — πŸ”Ή Step 2: Find \(g(h(x))\)

Let [x] denote the greatest integer less than or equal to x . If f(x)=sin^βˆ’1x, g(x)=[x^2] and h(x)=2x, 1/2≀x≀1/√2, then Read More Β»

If f : Rβ†’(βˆ’1,1) is defined by f(x)=βˆ’x∣x∣/(1+x^2), then f^βˆ’1(x) equals

Inverse Function Find \(f^{-1}(x)\) πŸŽ₯ Video Explanation πŸ“ Question \[ f(x)=\frac{-x|x|}{1+x^2}, \quad f:\mathbb{R}\to(-1,1) \] Find \(f^{-1}(x)\). βœ… Solution πŸ”Ή Step 1: Case-wise Expression For \(x \ge 0\): \[ f(x)=\frac{-x^2}{1+x^2} \] For \(x < 0\): \[ f(x)=\frac{x^2}{1+x^2} \] — πŸ”Ή Step 2: Let \(y=f(x)\) Case 1: \[ y=\frac{x^2}{1+x^2} \Rightarrow x^2=\frac{y}{1-y} \] Case 2: \[ y=\frac{-x^2}{1+x^2} \Rightarrow

If f : Rβ†’(βˆ’1,1) is defined by f(x)=βˆ’x∣x∣/(1+x^2), then f^βˆ’1(x) equals Read More Β»