Educational

Let f : [2, ∞) → X be defined by f(x) = 4x−x^2. Then, f is invertible, if X = (a) [2,∞) (b) (- ∞, 2] (c) (-∞, 4] (d) [4,∞)

Invertible Function Find Set \(X\) for Invertibility 🎥 Video Explanation 📝 Question Let \( f:[2,\infty)\to X \), \[ f(x)=4x-x^2 \] (a) \([2,\infty)\) (b) \((-\infty,2]\) (c) \((-\infty,4]\) (d) \([4,\infty)\) ✅ Solution 🔹 Step 1: Rewrite \[ f(x)=4x-x^2 \] \[ =-(x^2-4x) =-(x-2)^2+4 \] — 🔹 Step 2: Domain Analysis Given domain: \([2,\infty)\) Function is decreasing on this […]

Let f : [2, ∞) → X be defined by f(x) = 4x−x^2. Then, f is invertible, if X = (a) [2,∞) (b) (- ∞, 2] (c) (-∞, 4] (d) [4,∞) Read More »

The distinct linear functions which map [–1, 1] onto [0, 2] are A. f(x) = x + 1, g(x) = – x + 1 B. f(x) = x – 1, g(x) = x + 1 C. f(x) = –x – 1 g(x) = x – 1 D. none of these

Linear Function Mapping Find Linear Functions Mapping Intervals 🎥 Video Explanation 📝 Question Find all linear functions mapping \([-1,1]\) onto \([0,2]\). A. \(f(x)=x+1,\; g(x)=-x+1\) B. \(f(x)=x-1,\; g(x)=x+1\) C. \(f(x)=-x-1,\; g(x)=x-1\) D. none of these ✅ Solution 🔹 Step 1: General Form Let: \[ f(x)=ax+b \] — 🔹 Step 2: Endpoint Mapping Case 1: Increasing function

The distinct linear functions which map [–1, 1] onto [0, 2] are A. f(x) = x + 1, g(x) = – x + 1 B. f(x) = x – 1, g(x) = x + 1 C. f(x) = –x – 1 g(x) = x – 1 D. none of these Read More »

Let f(x) = αx/(x+1), x ≠ −1. Then, for what value of a is f(f(x)) = x ? (a) √2 (b) -√2 (c) 1 (d) -1

Function Composition Find \(\alpha\) such that \(f(f(x))=x\) 🎥 Video Explanation 📝 Question Given: \[ f(x)=\frac{\alpha x}{x+1}, \quad x\ne -1 \] Find \(\alpha\) such that: \[ f(f(x))=x \] (a) \(\sqrt{2}\) (b) \(-\sqrt{2}\) (c) \(1\) (d) \(-1\) ✅ Solution 🔹 Step 1: Compute \(f(f(x))\) \[ f(f(x)) = f\!\left(\frac{\alpha x}{x+1}\right) \] \[ = \frac{\alpha \cdot \frac{\alpha x}{x+1}}{\frac{\alpha x}{x+1}+1}

Let f(x) = αx/(x+1), x ≠ −1. Then, for what value of a is f(f(x)) = x ? (a) √2 (b) -√2 (c) 1 (d) -1 Read More »

Let g(x)=1+x−[x] and f(x)={​−1, x less than0 : 0, x=0 : 1, x greater than 0 ​, where [x] denotes the ​greatest integer less than or equal to x. Then for all x ,f(g(x)) is equal to (a) x (b) 1 (c) f(x) (d) g(x)

Function Composition Evaluate \(f(g(x))\) 🎥 Video Explanation 📝 Question Given: \[ g(x)=1+x-[x] \] \[ f(x)= \begin{cases} -1, & x0 \end{cases} \] (a) \(x\) (b) \(1\) (c) \(f(x)\) (d) \(g(x)\) ✅ Solution 🔹 Step 1: Understand \(g(x)\) \[ x-[x] \in [0,1) \] So: \[ g(x)=1+(x-[x]) \in [1,2) \] — 🔹 Step 2: Apply \(f\) Since \(g(x)

Let g(x)=1+x−[x] and f(x)={​−1, x less than0 : 0, x=0 : 1, x greater than 0 ​, where [x] denotes the ​greatest integer less than or equal to x. Then for all x ,f(g(x)) is equal to (a) x (b) 1 (c) f(x) (d) g(x) Read More »

If F: [1,∞)→[2,∞) is given by f(x) = x + 1/x, then f^−1(x) equals.

Inverse Function Find \(f^{-1}(x)\) 🎥 Video Explanation 📝 Question Let \( f:[1,\infty) \to [2,\infty) \), \[ f(x)=x+\frac{1}{x} \] Find \(f^{-1}(x)\). ✅ Solution 🔹 Step 1: Let \(y=f(x)\) \[ y=x+\frac{1}{x} \] — 🔹 Step 2: Multiply \[ yx=x^2+1 \] \[ x^2-yx+1=0 \] — 🔹 Step 3: Solve Quadratic \[ x=\frac{y\pm\sqrt{y^2-4}}{2} \] — 🔹 Step 4: Choose

If F: [1,∞)→[2,∞) is given by f(x) = x + 1/x, then f^−1(x) equals. Read More »

If the function f:R→R be such that f(x)=x−[x], where [x] denotes the greatest integer less than or equal to x, then f^−1(x) is (a) 1/(x-[x]) (b) [x] – x (c) not defined (d) none of these

Inverse of Greatest Integer Function Find \(f^{-1}(x)\) 🎥 Video Explanation 📝 Question Let \( f:\mathbb{R} \to \mathbb{R} \), \[ f(x)=x-[x] \] Find \(f^{-1}(x)\). (a) \(\frac{1}{x-[x]}\) (b) \([x]-x\) (c) not defined (d) none of these ✅ Solution 🔹 Step 1: Understand Function \[ f(x)=x-[x] \] This is the fractional part of \(x\). \[ f(x)\in[0,1) \] —

If the function f:R→R be such that f(x)=x−[x], where [x] denotes the greatest integer less than or equal to x, then f^−1(x) is (a) 1/(x-[x]) (b) [x] – x (c) not defined (d) none of these Read More »

Let f(x) = 1/(1−x) .Then, {fo(fof)}(x) A. x for all x∈R B. x for all x∈R−{1} C. x for all x∈R−{0,1} D. none of these

Function Composition Find \(f\circ(f\circ f)(x)\) 🎥 Video Explanation 📝 Question Given: \[ f(x)=\frac{1}{1-x} \] Find: \[ f(f(f(x))) \] A. \(x\) for all \(x\in\mathbb{R}\) B. \(x\) for all \(x\in\mathbb{R}\setminus\{1\}\) C. \(x\) for all \(x\in\mathbb{R}\setminus\{0,1\}\) D. none of these ✅ Solution 🔹 Step 1: Compute \(f(f(x))\) \[ f(f(x)) = f\!\left(\frac{1}{1-x}\right) \] \[ = \frac{1}{1-\frac{1}{1-x}} \] \[ =

Let f(x) = 1/(1−x) .Then, {fo(fof)}(x) A. x for all x∈R B. x for all x∈R−{1} C. x for all x∈R−{0,1} D. none of these Read More »

Let A={x∈R:x≤1} and f:A→ A given by f(x)=x(2−x). Then, f^−1(x) is (a) 1+ √1-x (b) 1-√1-x (c) √1-x (d) 1±√1-x

Inverse Function Find \(f^{-1}(x)\) 🎥 Video Explanation 📝 Question Let \(A=\{x\in\mathbb{R}:x\le1\}\) \[ f(x)=x(2-x) \] (a) \(1+\sqrt{1-x}\) (b) \(1-\sqrt{1-x}\) (c) \(\sqrt{1-x}\) (d) \(1\pm\sqrt{1-x}\) ✅ Solution 🔹 Step 1: Rewrite Function \[ f(x)=2x-x^2 \] \[ =1-(x-1)^2 \] — 🔹 Step 2: Let \(y=f(x)\) \[ y=1-(x-1)^2 \] — 🔹 Step 3: Solve for \(x\) \[ (x-1)^2=1-y \] \[

Let A={x∈R:x≤1} and f:A→ A given by f(x)=x(2−x). Then, f^−1(x) is (a) 1+ √1-x (b) 1-√1-x (c) √1-x (d) 1±√1-x Read More »

Let A={x∈R:x≥1}. The inverse of the function f:A→A given by f(x)=2^x(x−1), is

Inverse Function Find \(f^{-1}(x)\) 🎥 Video Explanation 📝 Question Let \(A=\{x\in\mathbb{R}:x\ge1\}\). \[ f(x)=2^x(x-1) \] Find \(f^{-1}(x)\). ✅ Solution 🔹 Step 1: Let \(y=f(x)\) \[ y=2^x(x-1) \] — 🔹 Step 2: Try Substitution Let \(t=x-1\) ⇒ \(x=t+1\) \[ y=2^{t+1}\cdot t = 2\cdot 2^t \cdot t \] \[ \frac{y}{2}=t\cdot 2^t \] — 🔹 Step 3: Recognize Form

Let A={x∈R:x≥1}. The inverse of the function f:A→A given by f(x)=2^x(x−1), is Read More »

The inverse of the function f:R→[x∈R:x less than1] given by f(x)= (e^x−e^−x)/(e^x+e^−x) , is

Inverse Hyperbolic Function Find \(f^{-1}(x)\) 🎥 Video Explanation 📝 Question Let \( f:\mathbb{R} \to (-1,1) \) be defined by \[ f(x)=\frac{e^x-e^{-x}}{e^x+e^{-x}} \] Find \(f^{-1}(x)\). ✅ Solution 🔹 Step 1: Recognize Form \[ f(x)=\tanh x \] — 🔹 Step 2: Let \(y=f(x)\) \[ y=\frac{e^x-e^{-x}}{e^x+e^{-x}} \] — 🔹 Step 3: Solve for \(x\) Multiply: \[ y(e^x+e^{-x})=e^x-e^{-x} \]

The inverse of the function f:R→[x∈R:x less than1] given by f(x)= (e^x−e^−x)/(e^x+e^−x) , is Read More »