Prove that: cos(π/5) cos(2π/5) cos(4π/5) cos(8π/5) = -1/16
Prove that cos(π/5) cos(2π/5) cos(4π/5) cos(8π/5) = -1/16 Prove that: cos(π/5) cos(2π/5) cos(4π/5) cos(8π/5) = -1/16 Question Prove that \[ \cos\frac{\pi}{5} \cos\frac{2\pi}{5} \cos\frac{4\pi}{5} \cos\frac{8\pi}{5} = -\frac{1}{16} \] Solution Using the identity \[ 2\sin\theta\cos\theta=\sin2\theta \] Start with \[ \cos\frac{\pi}{5} \cos\frac{2\pi}{5} \cos\frac{4\pi}{5} \cos\frac{8\pi}{5} \] Multiply and divide by \[ \sin\frac{\pi}{5} \] \[ = \frac{ \sin\frac{\pi}{5} \cos\frac{\pi}{5} \cos\frac{2\pi}{5} […]
Prove that: cos(π/5) cos(2π/5) cos(4π/5) cos(8π/5) = -1/16 Read More »