Educational

If A and B are square matrices of the same order such that AB = BA, then show that (A + B)^2 = A^2 + 2AB + B^2

Prove (A+B)² = A² + 2AB + B² Question If \(A\) and \(B\) are square matrices such that \(AB = BA\), prove that \[ (A + B)^2 = A^2 + 2AB + B^2. \] Solution Step 1: Expand \[ (A + B)^2 = (A + B)(A + B) \] \[ = A^2 + AB + […]

If A and B are square matrices of the same order such that AB = BA, then show that (A + B)^2 = A^2 + 2AB + B^2 Read More »

Let A and B be square matrices of the other 3×3. Is (AB)^2 = A^2 B^2 ? Give reasons.

Is (AB)² = A²B²? Question Let \(A\) and \(B\) be square matrices of order \(3 \times 3\). Is \[ (AB)^2 = A^2 B^2? \] Give reasons. Solution Step 1: Expand LHS \[ (AB)^2 = (AB)(AB) \] \[ = A(BA)B \] Step 2: Compare with RHS \[ A^2 B^2 = AABB \] Step 3: Key Observation

Let A and B be square matrices of the other 3×3. Is (AB)^2 = A^2 B^2 ? Give reasons. Read More »

If A and B are square matrices of the same order, explain, why in general (A + B)(A – B) ≠ A^2 – B^2

Why (A+B)(A-B) ≠ A² − B² Question If \(A\) and \(B\) are square matrices of the same order, explain why in general \[ (A + B)(A – B) \ne A^2 – B^2. \] Solution Step 1: Expand \[ (A + B)(A – B) \] \[ = A(A – B) + B(A – B) \] \[

If A and B are square matrices of the same order, explain, why in general (A + B)(A – B) ≠ A^2 – B^2 Read More »

If A and B are square matrices of the same order, explain, why in general (A – B)^2 ≠ A^2 – 2AB + B^2

Why (A-B)² ≠ A² − 2AB + B² Question If \(A\) and \(B\) are square matrices of the same order, explain why in general \[ (A – B)^2 \ne A^2 – 2AB + B^2. \] Solution Step 1: Expand \((A-B)^2\) \[ (A – B)^2 = (A – B)(A – B) \] \[ = A^2 –

If A and B are square matrices of the same order, explain, why in general (A – B)^2 ≠ A^2 – 2AB + B^2 Read More »

If A and B are square matrices of the same order, explain, why in general (A + B)^2 ≠ A^2 + 2AB + B^2

Why (A+B)² ≠ A² + 2AB + B² Question If \(A\) and \(B\) are square matrices of the same order, explain why in general \[ (A + B)^2 \ne A^2 + 2AB + B^2. \] Solution Step 1: Expand \((A+B)^2\) \[ (A + B)^2 = (A + B)(A + B) \] \[ = A^2 +

If A and B are square matrices of the same order, explain, why in general (A + B)^2 ≠ A^2 + 2AB + B^2 Read More »

Let A and B be square matrix of the same order. Does (A + B)^2 = A^2 + 2AB + B^2 hold ? If not, why?

Matrix Identity (A+B)² Question Let \(A\) and \(B\) be square matrices of the same order. Does \[ (A + B)^2 = A^2 + 2AB + B^2 \] hold? If not, why? Solution Step 1: Expand \((A+B)^2\) \[ (A + B)^2 = (A + B)(A + B) \] \[ = A^2 + AB + BA +

Let A and B be square matrix of the same order. Does (A + B)^2 = A^2 + 2AB + B^2 hold ? If not, why? Read More »