Find a Quadratic Polynomial Whose Sum and Product of Zeros Are −2√3 and −9 and Find Its Zeros by Factorisation
Video Explanation
Watch the video explanation below:
Solution
Given:
Sum of zeros = −2√3
Product of zeros = −9
Step 1: Form the Quadratic Polynomial
If sum of zeros = α + β and product of zeros = αβ, then the quadratic polynomial is:
x² − (α + β)x + αβ
∴ Required polynomial:
x² − (−2√3)x − 9
x² + 2√3x − 9
Step 2: Find the Zeros by Factorisation
x² + 2√3x − 9 = 0
Split the middle term:
x² + 3√3x − √3x − 9 = 0
Grouping the terms:
x(x + 3√3) − √3(x + 3√3) = 0
(x + 3√3)(x − √3) = 0
∴ x + 3√3 = 0 or x − √3 = 0
∴ x = −3√3 or x = √3
Zeros of the polynomial are −3√3 and √3.
Step 3: Verification
Let α = −3√3 and β = √3
Sum of zeros:
α + β = −3√3 + √3 = −2√3
✔ Verified
Product of zeros:
αβ = (−3√3)(√3) = −9
✔ Verified
Final Answer
Required quadratic polynomial is x² + 2√3x − 9.
Zeros of the polynomial are −3√3 and √3.
Conclusion
Thus, the quadratic polynomial formed using the given sum and product of zeros satisfies all the required conditions, and its zeros are obtained correctly by the factorisation method.