Solve the System of Linear Equations Using Cross-Multiplication Method

Video Explanation

Watch the video below to understand the complete solution step by step:

Solution

Question: Solve the following system of equations using cross-multiplication method:

(b/a)x + (a/b)y = a2 + b2  …… (1)

x + y = 2ab  …… (2)

Step 1: Convert Equation (1) into Linear Form

Multiply equation (1) by ab:

b2x + a2y = ab(a2 + b2)  …… (1)

Step 2: Write Equations in Standard Form

b2x + a2y − ab(a2 + b2) = 0  …… (1)

x + y − 2ab = 0  …… (2)

Step 3: Compare with ax + by + c = 0

From equation (1): a1 = b2, b1 = a2, c1 = −ab(a2 + b2)

From equation (2): a2 = 1, b2 = 1, c2 = −2ab

Step 4: Apply Cross-Multiplication Formula

x / (b1c2 − b2c1) = y / (a2c1 − a1c2) = 1 / (a1b2 − a2b1)

Substitute values:

x / [ a2(−2ab) − 1(−ab(a2 + b2)) ] = y / [ 1(−ab(a2 + b2)) − b2(−2ab) ] = 1 / [ b2(1) − 1(a2) ]

x / [ −2a3b + ab(a2 + b2) ] = y / [ −ab(a2 + b2) + 2ab3 ] = 1 / ( b2 − a2 )

x / [ ab(b2 − a2) ] = y / [ ab(a2 − b2) ] = 1 / ( b2 − a2 )

Step 5: Find the Values of x and y

x / [ ab(b2 − a2) ] = 1 / ( b2 − a2 )

⇒ x = ab

y / [ ab(a2 − b2) ] = 1 / ( b2 − a2 )

⇒ y = −ab

Final Answer

∴ The solution of the given system of equations is:

x = ab and y = −ab

Conclusion

Thus, by using the cross-multiplication method, we find that the solution of the given system of linear equations is (ab, −ab).

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