Relation Based on Relatively Prime Numbers

📺 Video Explanation

📝 Question

Let:

\[ A = \{3,5,7\}, \quad B = \{2,6,10\} \]

Relation \( R \) is defined as:

\[ R = \{(x,y) : x \in A,\ y \in B,\ \gcd(x,y) = 1\} \]

Find \( R \) and \( R^{-1} \).


✅ Solution

🔹 Step 1: Check Relatively Prime Pairs

Two numbers are relatively prime if:

\[ \gcd(x,y) = 1 \]

  • \( x = 3 \): (3,2) ✔, (3,6) ✖, (3,10) ✔
  • \( x = 5 \): (5,2) ✔, (5,6) ✔, (5,10) ✖
  • \( x = 7 \): (7,2) ✔, (7,6) ✔, (7,10) ✔

🔹 Step 2: Write Relation \( R \)

\[ R = \{(3,2), (3,10), (5,2), (5,6), (7,2), (7,6), (7,10)\} \]


🔹 Step 3: Find Inverse Relation \( R^{-1} \)

Swap each ordered pair:

\[ R^{-1} = \{(2,3), (10,3), (2,5), (6,5), (2,7), (6,7), (10,7)\} \]


🎯 Final Answer

\[ R = \{(3,2), (3,10), (5,2), (5,6), (7,2), (7,6), (7,10)\} \]

\[ R^{-1} = \{(2,3), (10,3), (2,5), (6,5), (2,7), (6,7), (10,7)\} \]


🚀 Exam Insight

  • Check gcd = 1 carefully
  • Prime numbers help simplify
  • Inverse = reverse pairs
  • Domain and range swap in inverse
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