Check Function \(f(x)=x^3-x\) on \( \mathbb{R} \)
📺 Video Explanation
📝 Question
Check whether the function
\[ f:\mathbb{R}\to\mathbb{R},\quad f(x)=x^3-x \]
is:
- injection (one-one)
- surjection (onto)
- bijection
✅ Solution
🔹 Step 1: Check Injection (One-One)
A function is one-one if different inputs give different outputs.
Take:
\[ x=-1,\quad x=0,\quad x=1 \]
Then:
\[ f(-1)=(-1)^3-(-1)=0 \]
\[ f(0)=0 \]
\[ f(1)=1-1=0 \]
Different inputs give same output.
❌ Not one-one.
🔹 Step 2: Check Surjection (Onto)
Since:
\[ \lim_{x\to\infty}(x^3-x)=\infty \]
and:
\[ \lim_{x\to-\infty}(x^3-x)=-\infty \]
Function is continuous on \(\mathbb{R}\).
By Intermediate Value Theorem, it takes every real value.
✔ Onto.
🎯 Final Answer
\[ \boxed{\text{f is onto but not one-one}} \]
So:
❌ Injection
✔ Surjection
❌ Bijection
🚀 Exam Shortcut
- Try small values for injection test
- Odd degree continuous polynomials cover all reals
- So cubic-type functions are onto