If a ∈ {-1, 2, 3, 4, 5} and b ∈ {0, 3, 6}, Write Ordered Pairs (a, b) Such That a + b = 5 If \(a \in \{-1,2,3,4,5\}\) and \(b \in \{0,3,6\}\), Write the Set of All Ordered Pairs \((a,b)\) Such That \(a+b=5\) Question If \[ a \in \{-1,2,3,4,5\} \] and \[ b […]

If Ordered Pairs (x, −1) and (5, y) Belong to the Set {(a, b) : b = 2a − 3}, Find x and y If the Ordered Pairs \( (x,-1) \) and \( (5,y) \) Belong to the Set \( \{(a,b): b=2a-3\} \), Find \(x\) and \(y\) Question If the ordered pairs \[ (x,-1) \]

If (x + 1, 1) = (3, y − 2), Find the Values of x and y If \( (x+1,\ 1) = (3,\ y-2) \), Find the Values of \(x\) and \(y\) Question If \[ (x+1,\ 1)=(3,\ y-2) \] find the values of \(x\) and \(y\). Solution Since two ordered pairs are equal, their corresponding

Let \(S\) = the set of points inside the square, \(T\) = the set of points inside the triangle and \(C\) = the set of points inside the circle. If the triangle and circle intersect each other and are contained in a square. Then, (a) \(S\cap T\cap C=\phi\) (b) \(S\cup T\cup C=C\) (c) \(S\cup T\cup

If (a/3 + 1, b − 2/3) = (5/3, 1/3), Find the Values of a and b If \( \left(\frac{a}{3}+1,\ b-\frac{2}{3}\right)=\left(\frac{5}{3},\ \frac{1}{3}\right) \), Find the Values of \(a\) and \(b\) Question If \[ \left(\frac{a}{3}+1,\ b-\frac{2}{3}\right)=\left(\frac{5}{3},\ \frac{1}{3}\right) \] find the values of \(a\) and \(b\). Solution Since two ordered pairs are equal, their corresponding components are

In a class of 60 students, 25 students play cricket and 20 students play tennis and 10 students play both the games. Then the number of students who play neither is (a) 0 (b) 25 (c) 35 (d) 45 Solution Let \[ n(C)=25 \] \[ n(T)=20 \] \[ n(C\cap T)=10 \] Using the formula, \[

In a town of 840 persons, 450 persons read Hindi, 300 read English and 200 both. Then the number of persons who read neither is (a) 210 (b) 290 (c) 180 (d) 260 Solution Let \[ n(H)=450 \] \[ n(E)=300 \] \[ n(H\cap E)=200 \] Using the formula, \[ n(H\cup E)=n(H)+n(E)-n(H\cap E) \] \[ =450+300-200

Let \(S=\{x:x \text{ is a positive multiple of }3 \text{ less than }100\}\), \[ P=\{x:x \text{ is a prime less than }20\} \] Then, \(n(S)+n(P)\) is (a) 34 (b) 31 (c) 33 (d) 30 Solution Positive multiples of \(3\) less than \(100\): \[ 3,6,9,\ldots,99 \] Number of elements in \(S\): \[ \frac{99}{3}=33 \] Therefore, \[

If A and B are two sets, then \(A \cap (A \cup B)\) equals (a) \(A\) (b) \(B\) (c) \(\phi\) (d) \(A\cap B\) Solution Using absorption law, \[ A\cap(A\cup B)=A \] Answer \[ \boxed{A} \] Correct option: (a) Next Question / Full Exercise

The set \((A \cup B \cup C) \cap (A \cap B′ \cap C′)′ \cup C′\) is equal to (a) \(B \cap C’\) (b) \(A \cap C\) (c) \(B \cup C’\) (d) \(A \cap C’\) Solution \[ (A\cup B\cup C)\cap(A\cap B’\cap C’)’\cup C’ \] Using De Morgan’s law, \[ (A\cap B’\cap C’)’=A’\cup B\cup C \] Therefore,