Let \(S\) = the set of points inside the square, \(T\) = the set of points inside the triangle and \(C\) = the set of points inside the circle.
If the triangle and circle intersect each other and are contained in a square. Then,
(a) \(S\cap T\cap C=\phi\)
(b) \(S\cup T\cup C=C\)
(c) \(S\cup T\cup C=S\)
(d) \(S\cup T=S\cap C\)
Solution
Since the triangle and the circle are both contained inside the square,
\[ T\subseteq S \]
and
\[ C\subseteq S \]
Therefore,
\[ S\cup T\cup C=S \]
Answer
\[ \boxed{S\cup T\cup C=S} \]
Correct option: (c)