In a class of 60 students, 25 students play cricket and 20 students play tennis and 10 students play both the games. Then the number of students who play neither is
(a) 0
(b) 25
(c) 35
(d) 45
Solution
Let
\[ n(C)=25 \]
\[ n(T)=20 \]
\[ n(C\cap T)=10 \]
Using the formula,
\[ n(C\cup T)=n(C)+n(T)-n(C\cap T) \]
\[ =25+20-10 \]
\[ =35 \]
Therefore, number of students who play neither:
\[ 60-35 \]
\[ =25 \]
Answer
\[ \boxed{25} \]
Correct option: (b)