Educational

If x, y, a, b are positive real numbers, prove that : (x^a/x^b)^c × (x^b/x^c)^a × (x^c/x^a)^b = 1

Proof of (x^a/x^b)^c (x^b/x^c)^a (x^c/x^a)^b = 1 Prove: \(\left(\frac{x^a}{x^b}\right)^c \times \left(\frac{x^b}{x^c}\right)^a \times \left(\frac{x^c}{x^a}\right)^b = 1\) Proof \[ = \left(x^{a-b}\right)^c \cdot \left(x^{b-c}\right)^a \cdot \left(x^{c-a}\right)^b \] \[ = x^{(a-b)c} \cdot x^{(b-c)a} \cdot x^{(c-a)b} \] \[ = x^{ac – bc + ab – ac + bc – ab} \] \[ = x^0 \] \[ = 1 \] Hence […]

If x, y, a, b are positive real numbers, prove that : (x^a/x^b)^c × (x^b/x^c)^a × (x^c/x^a)^b = 1 Read More »

Statement-1 (Assertion): The decimal representation of 3/8 is terminating. Statement-2 (Reason): If the denominator of a rational number is of the form 2^m x 2^n where m, n are non-negative integers, then its representation is terminating.

Assertion Reason MCQ on Decimal Expansion Question Statement-1 (Assertion): The decimal representation of \( \frac{3}{8} \) is terminating. Statement-2 (Reason): If the denominator of a rational number is of the form \(2^m \times 5^n\), where \(m, n\) are non-negative integers, then its decimal representation is terminating. Options: (a) Statement-1 is true, Statement-2 is true; Statement-2

Statement-1 (Assertion): The decimal representation of 3/8 is terminating. Statement-2 (Reason): If the denominator of a rational number is of the form 2^m x 2^n where m, n are non-negative integers, then its representation is terminating. Read More »