Find: \(a^a + b^b\), where \(a = 3, b = -2\)

Solution

\[ = 3^3 + (-2)^{-2} \]

\[ = 27 + \frac{1}{4} \]

\[ = \frac{109}{4} \]

Final Answer:

\[ \boxed{\frac{109}{4}} \]

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