Find: \(a^b + b^a\), where \(a = 3, b = -2\)
Solution
\[ = 3^{-2} + (-2)^3 \]
\[ = \frac{1}{9} – 8 \]
\[ = -\frac{71}{9} \]
Final Answer:
\[ \boxed{-\frac{71}{9}} \]
\[ = 3^{-2} + (-2)^3 \]
\[ = \frac{1}{9} – 8 \]
\[ = -\frac{71}{9} \]
\[ \boxed{-\frac{71}{9}} \]