Find (a + b)^ab when a = 3, b = -2

Find: \((a + b)^{ab}\), where \(a = 3, b = -2\)

Solution

\[ = (3 – 2)^{-6} \]

\[ = 1^{-6} \]

\[ = 1 \]

Final Answer:

\[ \boxed{1} \]

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