If tan θ₁ tan θ₂ = k, then (cos(θ₁ – θ₂) / cos(θ₁ + θ₂)) = (a) (1 + k)/(1 – k) (b) (1 – k)/(1 + k) (c) (k + 1)/(k – 1) (d) (k – 1)/(k + 1)
If tan θ₁ tan θ₂ = k, Find cos(θ₁ − θ₂) / cos(θ₁ + θ₂) If tan θ₁ tan θ₂ = k, Find cos(θ₁ − θ₂) / cos(θ₁ + θ₂) Question: If \[ \tan\theta_1\tan\theta_2=k \] then \[ \frac{\cos(\theta_1-\theta_2)} {\cos(\theta_1+\theta_2)} \] is equal to (a) \(\frac{1+k}{1-k}\) (b) \(\frac{1-k}{1+k}\) (c) \(\frac{k+1}{k-1}\) (d) \(\frac{k-1}{k+1}\) Solution Using the identities: […]