Check Function \(f(x)=x^2+x\) on \( \mathbb{Z} \)
📺 Video Explanation
📝 Question
Check whether the function
\[ f:\mathbb{Z}\to\mathbb{Z},\quad f(x)=x^2+x \]
is:
- injection (one-one)
- surjection (onto)
- bijection
✅ Solution
🔹 Step 1: Check Injection (One-One)
A function is one-one if:
\[ f(x_1)=f(x_2)\Rightarrow x_1=x_2 \]
Take:
\[ x=1,\quad x=-2 \]
Then:
\[ f(1)=1^2+1=2 \]
\[ f(-2)=(-2)^2+(-2)=4-2=2 \]
But:
\[ 1\neq-2 \]
❌ Not one-one.
🔹 Step 2: Check Surjection (Onto)
For onto, every integer must have pre-image.
Take:
\[ y=1 \]
Need:
\[ x^2+x=1 \]
or:
\[ x^2+x-1=0 \]
This equation has no integer solution.
So:
\[ 1 \]
is not in range.
❌ Not onto.
🎯 Final Answer
\[ \boxed{\text{f is neither one-one nor onto}} \]
So:
❌ Injection
❌ Surjection
❌ Bijection
🚀 Exam Shortcut
- Try small values to test injection
- Find missing codomain value to test onto
- Quadratic functions on integers usually fail bijection