Inverse of a for a*b = a + b + ab

Question:

Let \( * \) be defined on \( \mathbb{R} – \{-1\} \) by:

\[ a * b = a + b + ab \]

Find the inverse of \( a \).

Options:

  • (a) \( -a \)
  • (b) \( -\frac{a}{a+1} \)
  • (c) \( \frac{1}{a} \)
  • (d) \( a^2 \)

Solution:

Step 1: Find identity element

Let identity be \( e \), then:

\[ a * e = a \Rightarrow a + e + ae = a \]

\[ e + ae = 0 \Rightarrow e(1 + a) = 0 \]

Since \( a \neq -1 \), we get:

\[ e = 0 \]

Step 2: Find inverse of \( a \)

Let inverse be \( x \), then:

\[ a * x = 0 \]

\[ a + x + ax = 0 \]

\[ x(1 + a) = -a \Rightarrow x = -\frac{a}{a+1} \]

Final Answer:

\[ \boxed{-\frac{a}{a+1}} \]

Correct Option: (b)

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