Example of a One-One but Not Onto Function
📺 Video Explanation
📝 Question
Give an example of a function which is:
(i) one-one but not onto.
✅ Solution
Consider the function:
\[ f:\mathbb{N}\to\mathbb{N} \]
defined by:
\[ f(x)=x+1 \]
🔹 Check One-One (Injective)
Assume:
\[ f(x_1)=f(x_2) \]
Then:
\[ x_1+1=x_2+1 \]
So:
\[ x_1=x_2 \]
✔ Therefore, function is one-one.
🔹 Check Onto (Surjective)
For onto, every element in codomain must have a pre-image.
But:
\[ 1\in\mathbb{N} \]
There is no natural number \(x\) such that:
\[ x+1=1 \]
because:
\[ x=0 \]
and \(0\notin\mathbb{N}\) (school convention).
❌ So function is not onto.
🎯 Final Answer
An example is:
\[ \boxed{f(x)=x+1,\quad f:\mathbb{N}\to\mathbb{N}} \]
This function is one-one but not onto.
🚀 Exam Shortcut
- \(f(x)=x+1\) on natural numbers is a standard example
- Shifting by 1 keeps uniqueness
- First number in codomain is missed → not onto