Finding the Third Zero of a Cubic Polynomial

Video Explanation

Question

If two zeroes of the polynomial

\[ f(x) = x^3 + x^2 – 9x – 9 \]

are \(3\) and \(-3\), find its third zero.

Options:

(a) -1    (b) 1    (c) -9    (d) 9

Solution

Step 1: Use the Formula for Sum of Zeroes

For a cubic polynomial \[ ax^3 + bx^2 + cx + d, \]

the sum of its zeroes is:

\[ -\frac{b}{a} \]

Step 2: Apply to the Given Polynomial

Given:

\[ f(x) = x^3 + x^2 – 9x – 9 \]

Here,

\[ a = 1, \quad b = 1 \]

So, the sum of all three zeroes is:

\[ -\frac{1}{1} = -1 \]

Step 3: Use the Given Zeroes

Sum of the two given zeroes:

\[ 3 + (-3) = 0 \]

Let the third zero be \( \alpha \).

Then,

\[ 0 + \alpha = -1 \]

\[ \alpha = -1 \]

Conclusion

The third zero of the polynomial is:

\[ \boxed{-1} \]

Hence, the correct option is (a) -1.