Prove That (5 + 3√2) Is an Irrational Number
Video Explanation
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Solution
Question: Given that √2 is irrational, prove that (5 + 3√2) is an irrational number.
Proof:
Let us assume that (5 + 3√2) is a rational number.
Since 5 is a rational number, subtracting 5 from both sides, we get:
3√2 = (5 + 3√2) − 5
This implies that 3√2 is a rational number.
Dividing both sides by 3 (which is a non-zero rational number), we get:
√2 is a rational number.
But this contradicts the given fact that √2 is irrational.
∴ Our assumption is wrong.
Hence, (5 + 3√2) is an irrational number.
Final Answer
∴ (5 + 3√2) is an irrational number.
Conclusion
Thus, using the method of contradiction and the fact that √2 is irrational, we have proved that (5 + 3√2) is irrational.