Show That the Following Numbers Are Irrational

Video Explanation

Watch the video below for a detailed NCERT-based explanation:

Solution

Question: Show that the following numbers are irrational:

(i) 1/√2    (ii) 7√5    (iii) 6 + √2    (iv) 3 − √5


(i) Prove that 1/√2 is irrational

We know that √2 is an irrational number.

Let us assume that 1/√2 is rational.

Then its reciprocal √2 must also be rational, because the reciprocal of a non-zero rational number is rational.

But this contradicts the fact that √2 is irrational.

∴ Our assumption is wrong.

Hence, 1/√2 is irrational.


(ii) Prove that 7√5 is irrational

We know that √5 is an irrational number.

Let us assume that 7√5 is rational.

Since 7 is a non-zero rational number, dividing both sides by 7 gives:

√5 = (7√5) / 7

This implies that √5 is rational, which is a contradiction.

∴ Our assumption is wrong.

Hence, 7√5 is irrational.


(iii) Prove that 6 + √2 is irrational

Let us assume that 6 + √2 is rational.

Since 6 is a rational number, subtracting 6 from both sides gives:

√2 = (6 + √2) − 6

This implies that √2 is rational, which is a contradiction.

∴ Our assumption is wrong.

Hence, 6 + √2 is irrational.


(iv) Prove that 3 − √5 is irrational

Let us assume that 3 − √5 is rational.

Since 3 is a rational number, subtracting both sides from 3 gives:

√5 = 3 − (3 − √5)

This implies that √5 is rational, which is a contradiction.

∴ Our assumption is wrong.

Hence, 3 − √5 is irrational.


Final Answer

(i) 1/√2 is irrational
(ii) 7√5 is irrational
(iii) 6 + √2 is irrational
(iv) 3 − √5 is irrational

Conclusion

Thus, all the given numbers are proved to be irrational using the standard NCERT Class 10 method of contradiction.

Spread the love

Leave a Comment

Your email address will not be published. Required fields are marked *