Finding the Age of the Father
Video Explanation
Question
The age of the father is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children. Find the present age of the father.
Solution
Step 1: Let the Variables
Let present age of father = \(x\) years
Let present sum of ages of two children = \(y\) years
Step 2: Form the Equations
Given:\[ x = 2y \]
\[ x – 2y = 0 \quad (1) \]
After 20 years:Father’s age = \(x + 20\)
Each child gains 20 years, so total increase = \(40\)
New sum of children’s ages = \(y + 40\)
According to condition:\[ x + 20 = y + 40 \]
\[ x – y = 20 \quad (2) \]
Step 3: Solve by Elimination
Subtract equation (1) from equation (2):\[ (x – y) – (x – 2y) = 20 – 0 \]
\[ x – y – x + 2y = 20 \]
\[ y = 20 \]
Step 4: Find the Value of x
\[ x = 2y = 2(20) \]
\[ x = 40 \]
Conclusion
Present age of the father:
\[ \boxed{40 \text{ years}} \]